A 285-kg load is lifted 22.0 m vertically with an acceleration a=0.170 g by a single cable.

Determine the tension in the cable. (N)

Determine the net work done on the load. (J)

Determine the work done by the cable on the load.

Determine the work done by gravity on the load.

Determine the final speed of the load assuming it started from rest.

tension=mg+ma

work done= force*distance

3240 N

Force due to tension = mg + ma

The force that the load originally has in addition to the force due to acceleration.

To determine the tension in the cable, we can use Newton's second law of motion: F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, the force is equal to the tension in the cable, so we have:

Tension = ma

Given that the mass of the load is 285 kg and the acceleration is 0.170 times the acceleration due to gravity (g), which is approximately 9.8 m/s^2, we can calculate the tension:

Tension = (285 kg) * (0.170 * 9.8 m/s^2)
Tension ≈ 477.994 N

So, the tension in the cable is approximately 477.994 N.

To determine the net work done on the load, we can use the work-energy theorem. The work done on an object is equal to the change in its kinetic energy. In this case, the load is initially at rest and lifted vertically, so its initial kinetic energy is zero. The final kinetic energy can be calculated using the equation:

Kinetic energy = (1/2) * mass * velocity^2

Since the load started from rest, the initial velocity is zero. The final velocity can be calculated using the following equations:

Final velocity^2 = initial velocity^2 + 2 * acceleration * distance

Given that the acceleration is 0.170 times g and the distance is 22.0 m, we can calculate the final velocity:

Final velocity^2 = 0^2 + 2 * (0.170 * 9.8 m/s^2) * 22.0 m
Final velocity ≈ 12.855 m/s

Now, we can calculate the net work done:

Net work = (1/2) * mass * final velocity^2
Net work = (1/2) * 285 kg * (12.855 m/s)^2
Net work ≈ 22157.569 J

So, the net work done on the load is approximately 22157.569 J.

The work done by the cable on the load is equal to the tension multiplied by the distance over which the force is applied. In this case, the distance is 22.0 m. Therefore,

Work done by the cable = Tension * distance
Work done by the cable = 477.994 N * 22.0 m
Work done by the cable ≈ 10555.868 J

So, the work done by the cable on the load is approximately 10555.868 J.

The work done by gravity on the load can be calculated using the equation:

Work done by gravity = m * g * height

Given that the mass of the load is 285 kg, the acceleration due to gravity is approximately 9.8 m/s^2, and the height is 22.0 m, we can calculate the work done by gravity:

Work done by gravity = 285 kg * 9.8 m/s^2 * 22.0 m
Work done by gravity ≈ 59802 J

So, the work done by gravity on the load is approximately 59802 J.

To determine the final speed of the load assuming it started from rest, we can use the equation:

Final velocity = initial velocity + acceleration * time

Since the load started from rest, the initial velocity is zero. The time can be calculated using the equation:

Distance = initial velocity * time + (1/2) * acceleration * time^2

Given that the distance is 22.0 m and the acceleration is 0.170 times g, we can solve for the time:

22.0 m = 0 * time + (1/2) * (0.170 * 9.8 m/s^2) * time^2

Solving this equation would yield the time it took for the load to move 22.0 m, but the equation is quadratic, and it has two solutions for time. One solution corresponds to the time when the load is at the start and the other corresponds to when it reaches a distance of 22.0 m. Since we know the initial velocity is zero, we discard the solution corresponding to the load being at the start.

Now, we can calculate the final velocity using the equation:

Final velocity = 0 + (0.170 * 9.8 m/s^2) * time

Substituting the calculated time into the equation would give us the final velocity of the load.