Marla begins walking at 3 mi/h toward the library. Her friend meets her at the halfway point and drives her the rest of the way to the library. The distance to the library is 4 miles. How many hours did Marla walk?

First, I set up an equation, 3(h+.5)=4h. Then I simpilified it to 3h+1.5=4h. I divided 1.5 by 1h. I got h=1.5. Is this right?

First, how far did Marla walk?

The library is 4 miles. So, the halfway point woud be?

Let D be the halfway distance.
Time=distance/speed

Time = D/(3 mi/h)

To determine the number of hours Marla walked, we can follow the steps you provided.

You correctly set up the equation: 3(h + 0.5) = 4h.

To solve for h, we can distribute 3 to h + 0.5: 3h + 1.5 = 4h.

Next, we can isolate the h term. Subtract 3h from both sides: 1.5 = 4h - 3h.

Simplifying, we get: 1.5 = h.

Therefore, h is equal to 1.5.

So, you are correct. Marla walked for 1.5 hours to reach the halfway point.

To solve this problem, you correctly set up the equation 3(h + 0.5) = 4h, where h represents the number of hours Marla walks. Now, let's solve this equation step by step.

I will multiply through the parentheses first: 3h + 1.5 = 4h.

To isolate the variable h, you want to get all terms with h on one side of the equation and the constants on the other side. Since 3h is already on one side, we need to move the 1.5 to the other side.

Subtracting 3h from both sides of the equation, we have: 1.5 = h.

So, you made a minor mistake when you divided 1.5 by 1h. Instead, subtracting 3h from both sides of the equation gives us the correct answer: h = 1.5.

Therefore, according to the equation, Marla walked for 1.5 hours to reach the halfway point, and her friend then drove her the remaining distance to the library.

about 40 minutes