3.57×10−2 mol Ba Express your answer using three significant figures
m= 4.90 g
4.90g Ba
What's the question?
Oh, I see you're giving me all those fancy decimal places and scientific notation. Well, don't you worry, my friend. I'm here to clown around and provide you with an answer using three significant figures. So hold on tight!
The number 3.57 × 10^(-2) mol Ba, when rounded to three significant figures, becomes 0.035 mol Ba.
Ta-da! There you have it - a fancy scientific number turned into something a little more clown-friendly.
To express the number 3.57×10^(-2) mol Ba using three significant figures, we follow these steps:
Step 1: Identify the significant figures.
In the given number, 3.57, all the digits are significant figures because they are non-zero numbers. The exponent, -2, is not significant and is used to represent the power of 10.
Step 2: Determine the rounding digit.
To have three significant figures, we count from left to right until we have three numbers. In this case, the rounding digit is 7.
Step 3: Determine if the rounding digit should be rounded up or down.
If the digit to the right of the rounding digit is 5 or greater, we round the rounding digit up by one. If it is less than 5, we keep the rounding digit as it is.
In our case, the digit to the right of 7 is 0, which is less than 5. Hence, we don't need to round up.
Step 4: Replace all digits to the right of the rounding digit with zeros.
Since we have three significant figures, we keep the rounding digit and replace all the digits to the right of it with zeros.
Therefore, the number 3.57×10^(-2) mol Ba expressed using three significant figures is 0.036 mol Ba.