What is the cube root of x to the 7th power?
Out of seven x's
Take an x out and leave six x's
cube root of x^6= x squared
Leave it as that times the cube root of that x that you took out.
x squared
To find the cube root of \(x\) to the 7th power, we can use the property of exponents that states that taking the cube root of a number raised to an exponent is equivalent to raising the number to the exponent divided by 3. Therefore, the cube root of \(x\) to the 7th power is \(x\) raised to the power of \(7/3\).
So, the cube root of \(x\) to the 7th power is \(x^{7/3}\).
To find the cube root of x raised to the 7th power, you can use the property of exponents that states taking the root of a number is the same as raising it to the power of 1 divided by that root. In this case, the cube root means raising to the power of 1/3.
So, to find the cube root of x to the 7th power, you can rewrite it as (x^7)^(1/3). Applying the property of exponents, you can multiply the exponents, which gives you x^(7 * 1/3). Simplifying further, you have x^(7/3) as the cube root of x to the 7th power.