If 456 dm^3 of krypton at 101 kPa and 21 degrees C is compressed into a 27.0 dm^3 tank at the same temperature, what is the pressure of krypton in the tank?
V1= 456 dm^3
V2= 27.0 dm^3
P1= 101 kPa
P2= ?
P2= 101 kPa * 456 dm^3/ 27.0 dm^3
ANSWER:
1705.78 kPa
Is this right??
Almost.
All of the digits are correct because the answer is a repeating number of 1705.7777777. However, you have only three (3) significant figures in the problem; therefore, you may have only 3 s.f. in the answer. So the answer should be rounded to 1.70 x 10^3. In rounding, and when the last number is a 5, I round to the nearest even number so the 0 stays and we drop the 5. Had the zero been a 1, we would have rounded up by making the 1 a 2 and droping the 5. And the scientific notation is necesssary in the answer because if we write it as 1700 we are showing four s.f.
To find the pressure of krypton in the tank, we can use Boyle's law formula which states that the product of initial pressure and initial volume is equal to the product of final pressure and final volume.
Boyle's Law Formula:
P1 * V1 = P2 * V2
Given values:
V1 = 456 dm^3
V2 = 27.0 dm^3
P1 = 101 kPa
P2 = ?
We can rearrange the formula to solve for P2:
P2 = P1 * V1 / V2
Substituting the given values:
P2 = 101 kPa * 456 dm^3 / 27.0 dm^3
Calculating:
P2 ≈ 1705.78 kPa
Therefore, the pressure of krypton in the tank is approximately 1705.78 kPa.
To find the pressure of krypton in the tank, you can use Boyle's Law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume.
Boyle's Law equation: P1 * V1 = P2 * V2
In this case, P1 is the initial pressure of krypton (101 kPa), V1 is the initial volume of krypton (456 dm^3), P2 is the final pressure of krypton in the tank (to be determined), and V2 is the final volume of krypton in the tank (27.0 dm^3).
Now we can substitute the given values into the equation:
101 kPa * 456 dm^3 = P2 * 27.0 dm^3
To solve for P2, divide both sides of the equation by 27.0 dm^3:
P2 = (101 kPa * 456 dm^3) / 27.0 dm^3
Calculating:
P2 = 1705.78 kPa
Therefore, the pressure of krypton in the tank is approximately 1705.78 kPa.