A solution is 40% acetic acid by mass. The density of this solution is 1.049 g/mL. Calcu- late the mass of pure acetic acid in 120 mL of this solution at 20 C.
40% means 40 g acetic acid/100 g soln.
The density is 1.049; therefore, the volume of 100 g soln is 100/1.049 = 95.328 mL. You want 120 mL of the solution; therefore,
40 x (120 mL/95.328 mL) = ?? g in 120 mL.
To check you answer, convert 120 mL to grams and divide (??g/g)*100 soln = should be 40
To calculate the mass of pure acetic acid in 120 mL of a 40% acetic acid solution, we can follow these steps:
Step 1: Calculate the mass of the solution.
To do this, we need to know the density of the solution and the volume (in mL) of the solution.
Density = mass/volume
Rearranging the equation, we can find the mass:
Mass = Density * Volume
Mass = 1.049 g/mL * 120 mL
Mass = 125.88 g
The mass of the solution is 125.88 g.
Step 2: Calculate the mass of the acetic acid in the solution.
Since the solution is 40% acetic acid by mass, we can convert this percentage into a decimal fraction (divide by 100):
Mass of acetic acid = 40% * Mass of solution
Mass of acetic acid = 0.40 * 125.88 g
Mass of acetic acid = 50.35 g
Therefore, the mass of pure acetic acid in 120 mL of a 40% acetic acid solution is approximately 50.35 g.
To calculate the mass of pure acetic acid in the solution, we need to consider the percentage of acetic acid and the density of the solution.
First, let's calculate the mass of the solution:
Mass of the solution = Volume of the solution × Density
= 120 mL × 1.049 g/mL
= 125.88 g
Next, we calculate the mass of acetic acid in the solution:
Mass of acetic acid = Mass of solution × Percentage of acetic acid / 100
= 125.88 g × 40 / 100
= 50.352 g
Therefore, the mass of pure acetic acid in 120 mL of this solution at 20 °C is 50.352 grams.