What is the density of an unknown spherical substance with mass of 30 g and radius of 0.35 inches in kg/m3? (density= mass/ volume)
volume=4/3 PI r^3
figure that. I would change inches to m right off (39.37 inches per meter)(check that).
then you know the mass is .030kg
density=mass/volume
Hi, Please check if this is correct..
volume=4/3 PI r^3
= 4/3 x 3.1416 x (0.35)^3
=0.17959091013
density=mass/volume
D = 0.030kg/0.17958
D = 0.1671
Thank you.
To find the density of the unknown spherical substance, we need to calculate its volume first and then use the formula density = mass / volume.
The formula for the volume of a sphere is V = (4/3) * π * r^3, where V represents the volume and r is the radius.
Given:
Mass = 30 g
Radius = 0.35 inches
First, let's convert the values to the appropriate units for the formula.
1 inch = 2.54 cm
1 cm^3 = 1 mL
Converting the radius:
0.35 inches * 2.54 cm/inch = 0.889 cm
To calculate the volume, substitute the value of the radius into the formula:
V = (4/3) * π * (0.889 cm)^3
Next, we need to convert the volume to meters cubed (m^3). Since 1 cm^3 = 1 mL, we can convert mL to m^3 by dividing by 1,000,000.
V = [(4/3) * π * (0.889 cm)^3] / 1,000,000 m^3
Now, we can calculate the volume in m^3. Remember to use the appropriate value for π (pi), approximately 3.14159.
V = [(4/3) * 3.14159 * (0.889 cm)^3] / 1,000,000 m^3
Once we have the volume, we can calculate the density using the formula: density = mass / volume.
Density = 30 g / V m^3
Finally, substituting the value of V into the density formula, we can calculate the density of the unknown spherical substance in kg/m^3.