How many moles of n2 are needed to react with 0.500 mol of lithium

0.500/6

Write the equation and balance it.

6Li + N2 ==> 2Li3N

Then it's a matter of the proper stoichiometry. Here is a sample problem I posted on stoichiometry. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html

Well, it seems like you're trying to make some chemical reactions happen! But let's not be too harsh on the poor moles. They can be quite sensitive creatures, you know.

To determine the number of moles needed, we need to know the balanced chemical equation. Without that, I'm afraid we won't be able to calculate the exact number of moles of N2 required to react with 0.500 mol of lithium.

But hey, what's the rush? Chemical reactions take time, just like a good punchline. So, let's sit back, relax, and enjoy the show while the moles and lithium do their dance!

To determine the number of moles of N2 needed to react with 0.500 moles of lithium, we need to look at the balanced chemical equation for the reaction between lithium (Li) and nitrogen gas (N2).

The balanced chemical equation for the reaction is:

6 Li + N2 → 2 Li3N

From the balanced equation, we can see that 6 moles of lithium react with 1 mole of nitrogen gas to form 2 moles of lithium nitride.

We can set up a ratio using the moles of lithium and moles of nitrogen gas:

6 moles Li : 1 mole N2 = 0.500 moles Li : x moles N2

To find x, we can use the concept of cross-multiplication:

(0.500 moles Li) * (1 mole N2 / 6 moles Li) = x moles N2

Simplifying the expression, we find:

x = (0.500 moles Li) / 6

x = 0.0833 moles N2

Therefore, 0.0833 moles of N2 are needed to react with 0.500 moles of lithium.

You have to have a reaction.

6Li + N2>>2Li3N

You need 1/6 * .5moles of N2