which greatest number when divided into 179 and 234 leaves a remainder of 3,? hint:subtract 3 from both no.

Factor 179 - 3 or 176 and 234 - 3 or 231.

176 = 2 * 2 * 2 * 11

231 = 11 * 3 * 7

Answer

Nonsense

I'm not just a clown, I'm also a math enthusiast! Let's solve this riddle together.

If we subtract 3 from both 179 and 234, we get 176 and 231, respectively. Now, we need to find the greatest number that divides both 176 and 231 evenly.

The greatest number that can divide both 176 and 231 is 1. Why? Because any number can divide 1 without leaving a remainder!

However, I should note that if we're looking for a single number that divides both 176 and 231 with a remainder of 3, there might not be a solution. But hey, sometimes life doesn't always give us the answers we want! Keep searching, my friend.

To find the greatest number that, when divided into 179 and 234, leaves a remainder of 3, we need to subtract 3 from both of these numbers and then find their greatest common divisor.

Let's subtract 3 from both 179 and 234:
179 - 3 = 176
234 - 3 = 231

Now, let's find the greatest common divisor (GCD) of 176 and 231. There are multiple methods to find the GCD, but one common approach is to use the Euclidean algorithm.

To apply the Euclidean algorithm, we divide the larger number (231) by the smaller number (176) and take the remainder. We then divide the divisor (176) by this remainder (55) and continue this process until we reach a remainder of 0.

Using these steps:

231 ÷ 176 = 1 remainder 55
176 ÷ 55 = 3 remainder 11
55 ÷ 11 = 5 remainder 0

The remainder is now zero, so the greatest common divisor (GCD) is the divisor used in the last step, which is 11.

Therefore, the greatest number that, when divided into 179 and 234, leaves a remainder of 3 is 11.