Calculate the number of grams required to make 250 mL of a 0.020 M KIO3 solution.
does it equal 1.07 g?
thank you
Well, if you want to make a 0.020 M KIO3 solution, you're going to need some potassium iodate (KIO3). Time to get all sciency and calculate!
To find the number of grams required, we need to know the molar mass of KIO3. So, let me look that up real quick... ah, here it is!
The molar mass of KIO3 is approximately 214 grams per mole (g/mol). Now, we can multiply the molarity by the volume in liters to find the number of moles. But to do that, we need to convert the mL to L.
Since 1 L is equal to 1000 mL, we can divide 250 mL by 1000 to get the volume in liters: 250 mL / 1000 = 0.25 L.
So, now we can calculate the number of moles: 0.020 M x 0.25 L = 0.005 moles.
Finally, we can convert moles to grams by multiplying by the molar mass: 0.005 moles x 214 g/mol = 1.07 grams.
Therefore, you would need approximately 1.07 grams of potassium iodate (KIO3) to make 250 mL of a 0.020 M solution.
To calculate the number of grams required to make a specific concentration solution, we will need to use the formula:
C = (molarity * volume) / (molecular weight)
where:
C = concentration in moles per liter (M)
molarity = concentration in moles per liter (M)
volume = volume in liters (L)
molecular weight = the molecular weight of the substance in grams per mole (g/mol)
In this case, the molarity is given as 0.020 M, and the volume is given as 250 mL. However, since the formula requires volume in liters, we need to convert mL to L by dividing by 1000:
volume = 250 mL / 1000 mL/L = 0.25 L
Now, we need to find the molecular weight of KIO3. The molecular weight can be calculated by summing the atomic weights of all the atoms in the chemical formula. In this case:
M(K) = 39.10 g/mol
M(I) = 126.90 g/mol
M(O) = 16.00 g/mol
So, the molecular weight of KIO3 is:
M(KIO3) = M(K) + M(I) + 3 * M(O)
= 39.10 + 126.90 + (3 * 16.00)
= 214.10 g/mol
Now, we can plug in the values into the formula to find the number of grams required:
C = (molarity * volume) / (molecular weight)
0.020 M = (molarity * 0.25 L) / 214.10 g/mol
Rearranging the formula to solve for the number of grams:
grams = (molarity * volume * molecular weight) / (1 M)
= (0.020 mol/L * 0.25 L * 214.10 g/mol) / (1 M)
Calculating this expression:
grams = (0.020 * 0.25 * 214.10) / 1
= 2.135 g
Therefore, approximately 2.135 grams of KIO3 are required to make 250 mL of a 0.020 M KIO3 solution.
.250 L X .020 mol X molar mass of KIO3
1 L 1 mol