what is the theoretical percent of water in CuSO4 x's 5H2O?
(5*molar mass H2O/molar mass CuSO4.5H2O)*100 = ??
To determine the theoretical percent of water in CuSO4 x 5H2O, we need to calculate the molar mass of water and the molar mass of CuSO4 x 5H2O.
1. Molar mass of water (H2O):
- The atomic mass of hydrogen (H) is approximately 1 gram/mole.
- The atomic mass of oxygen (O) is approximately 16 grams/mole.
- Since water has 2 hydrogen atoms and 1 oxygen atom, the molar mass of H2O is (2 x 1) + 16 = 18 grams/mole.
2. Molar mass of CuSO4 x 5H2O:
- The atomic mass of copper (Cu) is approximately 63.5 grams/mole.
- The atomic mass of sulfur (S) is approximately 32.1 grams/mole.
- The atomic mass of oxygen (O) is approximately 16 grams/mole.
- Since CuSO4 x 5H2O consists of one copper atom, one sulfur atom, four oxygen atoms, and five water molecules, the molar mass is (63.5) + (32.1) + (4 x 16) + (5 x 18) = 249.5 grams/mole.
3. Calculating the percent of water:
- The percent of water is determined by dividing the molar mass of water by the molar mass of the entire compound and multiplying by 100.
- (18 / 249.5) x 100% = approximately 7.21%.
So, the theoretical percent of water in CuSO4 x 5H2O is approximately 7.21%.
To determine the theoretical percent of water in CuSO4 x 5H2O, we need to consider the molar masses of water (H2O) and copper(II) sulfate (CuSO4).
The molar mass of water can be calculated by adding up the atomic masses of its constituents, which are hydrogen (H) and oxygen (O). The atomic mass of hydrogen is 1 g/mol and oxygen is 16 g/mol. Since water has two hydrogen atoms and one oxygen atom, the molar mass of water is 2(1 g/mol) + 1(16 g/mol) = 18 g/mol.
The molar mass of copper(II) sulfate can be calculated by adding up the atomic masses of its constituents, which are copper (Cu), sulfur (S), and oxygen (O). The atomic mass of copper is 63.5 g/mol, sulfur is 32 g/mol, and oxygen is 16 g/mol. Therefore, the molar mass of copper(II) sulfate is 63.5 g/mol + 32 g/mol + 4(16 g/mol) = 160.5 g/mol.
In the compound CuSO4 x 5H2O, there are five water molecules (H2O) associated with each copper(II) sulfate molecule (CuSO4). To calculate the mass of water in the compound, we can multiply the molar mass of water (18 g/mol) by the number of water molecules (5).
Mass of water = molar mass of water x number of water molecules
Mass of water = 18 g/mol x 5 = 90 g
Now, to calculate the theoretical percent of water in CuSO4 x 5H2O, we divide the mass of water by the molar mass of the whole compound and multiply the result by 100.
Theoretical percent of water = (mass of water / molar mass of CuSO4 x 5H2O) x 100
Theoretical percent of water = (90 g / (160.5 g/mol + 5(18 g/mol))) x 100
Calculating this expression will yield the theoretical percent of water in CuSO4 x 5H2O.