A 46.2-mL, 0.568 M calcium nitrate [Ca(NO3)2] solution is mixed with 80.5 mL of1.396 M calcium nitrate solution. calculate the concentration of the final solution

Not 100% sure if this is right, but here's what I think it is.

M = mol/L
.568 = mol/.0462 L
= .0262416 mol

1.396 = mol/.0805 L
= .112378 mol

(.0262416 mol + .112378 mol) / (.0462 L + .0805 L) = M

M = 1.0094077348

oops!

(.0262416 mol + .112378 mol) / (.0462 L + .0805 L) = M

M = 1.0941 and not 1.0094077

Thanks, the answer's 1.09M

Well, if we mix solutions, we usually assume that the volumes are additive. So, to calculate the concentration of the final solution, we can use the formula:

C1V1 + C2V2 = C3V3

Using this formula, we can substitute the given values:

(0.568 M)(46.2 mL) + (1.396 M)(80.5 mL) = C3(46.2 mL + 80.5 mL)

Now, let's plug in the numbers and solve for C3:

(0.568 M)(46.2 mL) + (1.396 M)(80.5 mL) = C3(126.7 mL)

25.9696 + 112.508 = C3(126.7)

138.4776 = C3(126.7)

Now, to get C3 by itself, we divide both sides by 126.7:

C3 = 138.4776 / 126.7

C3 ≈ 1.092 M

So, the concentration of the final solution is approximately 1.092 M. Now wasn't that calcium-uwonderful?

To calculate the concentration of the final solution, we can use the principle of the conservation of moles. The total moles of calcium nitrate before mixing should be equal to the total moles after mixing.

First, let's calculate the number of moles of calcium nitrate in each solution:

Number of moles of calcium nitrate in the 46.2 mL solution:
moles = volume (L) x molarity
moles = 46.2 mL x (1 L / 1000 mL) x 0.568 M
moles = 0.026256 mol

Number of moles of calcium nitrate in the 80.5 mL solution:
moles = 80.5 mL x (1 L / 1000 mL) x 1.396 M
moles = 0.112198 mol

Next, let's calculate the total moles of calcium nitrate after mixing both solutions:

total moles = moles in solution 1 + moles in solution 2
total moles = 0.026256 mol + 0.112198 mol
total moles = 0.138454 mol

Now, let's calculate the volume of the final solution by adding the volumes of the two solutions:

volume of final solution = volume of solution 1 + volume of solution 2
volume of final solution = 46.2 mL + 80.5 mL
volume of final solution = 126.7 mL

Finally, we can calculate the concentration of the final solution by dividing the total moles by the volume of the final solution:

concentration of final solution = total moles / volume of final solution
concentration of final solution = 0.138454 mol / (126.7 mL x (1 L / 1000 mL))
concentration of final solution = 1.092 M

Therefore, the concentration of the final solution is 1.092 M.