If a 0.5 -mL air bubble is persent in the tip of a buret, what error in 10-mL,20 m

l and 40-mL samples will result if the air bubble is dislodged during the dispensing of the sample?

I presume the question is looking for the percentage error

so 0.5 x 100%/10 for the 10 ml sample.

I do however question the size of the air bubble. Most burette tips are about 1 mm diameter and about 1 cm long. So if we have a bubble filling the whole tip the volume is

0.05 cm x 0.05 cm x 3.142 x 1 cm=

0.01 cm^3 to 1 sig fig.

7.86

7.86 or is it 1.00000000x10-6

To determine the potential error introduced by the dislodging of a 0.5-mL air bubble during the dispensing of samples, we can calculate the percent error for each sample size (10 mL, 20 mL, and 40 mL).

First, let's calculate the volume of the air bubble as a percentage of the sample size. Then, we'll multiply this percentage by the sample size to get the error value.

For a 10-mL sample:
Volume of air bubble = 0.5 mL
Percentage of sample size = (0.5 mL / 10 mL) * 100% = 5%
Error in 10 mL sample = 10 mL * (5% / 100) = 0.5 mL

For a 20-mL sample:
Volume of air bubble = 0.5 mL
Percentage of sample size = (0.5 mL / 20 mL) * 100% = 2.5%
Error in 20 mL sample = 20 mL * (2.5% / 100) = 0.5 mL

For a 40-mL sample:
Volume of air bubble = 0.5 mL
Percentage of sample size = (0.5 mL / 40 mL) * 100% = 1.25%
Error in 40 mL sample = 40 mL * (1.25% / 100) = 0.5 mL

Therefore, regardless of the sample size (10 mL, 20 mL, or 40 mL), dislodging the 0.5-mL air bubble during sample dispensing will result in a constant error of 0.5 mL.