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Anhydrous CuSO4 can be used to dry liquids in which it is insoluble. The CuSO4 is converted to CuSO4 x 5H20, which can be filtered off from the liquid. What is the minimum mass of anhydrous CuSO4 needed to remove 12.6 g H20 from a tankful of gasoline?

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2 answers
  1. RMM of CuSO4=(63.55+32+4*16)=159.55
    RMM of 5H2O = 5*(1*2+16)=90
    Use proportions,
    Amount of CuSO4 required
    =12.6g *(RMM CuSO4)/(RMM 5H2O)
    =?

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  2. 1*2+16=18
    5*18=90

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