A mixture of CuSO4 and CuSO4·5 H2O has a mass of 1.235 g. After heating to drive off all the water, the mass is only 0.830 g. What is the mass percent of CuSO4·5 H2O in the mixture?

Mass of H2O expelled = 1.235-0.830=0.405 g

RMM of 5H2O = 5*(2*1+16)=90

RMM of crystalline CuSO4
=63.55+32+4*16 + 90
=249.55

Therefore, by proportion, mass of crystalline CuSO4.5H2O
=0.405*(249.55/90)
=1.123g
Mass percentage of CuSO4.5H2O
=mass of CuSO4.5H2O / total mass
=?

Well, it seems like this mixture got a little steamy! If we subtract the mass after heating from the initial mass, we can find out the mass of water that was present.

Initial mass (CuSO4 + CuSO4·5 H2O): 1.235 g
Mass after heating (CuSO4): 0.830 g

Change in mass: 1.235 g - 0.830 g = 0.405 g

Now, let's calculate the mass percent of CuSO4·5 H2O in the mixture. We want to find the percent of CuSO4·5 H2O out of the total initial mass.

Mass percent = (Mass of CuSO4·5 H2O / Total initial mass) x 100

Mass of CuSO4·5 H2O = Change in mass = 0.405 g

Total initial mass = Initial mass (CuSO4 + CuSO4·5 H2O) = 1.235 g

Mass percent = (0.405 g / 1.235 g) x 100 = 32.8%

So, the mass percent of CuSO4·5 H2O in the mixture is approximately 32.8%. Remember, always be careful when handling chemicals, because sometimes they can turn into a disappearing act!

To find the mass percent of CuSO4·5 H2O in the mixture, we need to determine the mass of CuSO4·5 H2O and the initial mass of the mixture. Then we can calculate the mass percent using the formula:

Mass Percent = (Mass of CuSO4·5 H2O / Initial mass of the mixture) * 100

Let's break down the steps on how to get the answer:

1. Calculate the mass of CuSO4·5 H2O:
Mass of CuSO4·5 H2O = Initial mass of the mixture - Mass of the mixture after heating
Mass of CuSO4·5 H2O = 1.235 g - 0.830 g
Mass of CuSO4·5 H2O = 0.405 g

2. Calculate the mass percent of CuSO4·5 H2O:
Mass Percent = (Mass of CuSO4·5 H2O / Initial mass of the mixture) * 100
Mass Percent = (0.405 g / 1.235 g) * 100
Mass Percent = 32.8%

Therefore, the mass percent of CuSO4·5 H2O in the mixture is approximately 32.8%.

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