In an acid-base neutralization reaction 28.74 mL of 0.500 M potassium hydroxide reacts with 50.00 mL of sulfuric acid solution. What is the concentration of the H2SO4 solution?
Please help with this question, thank you.
To find the concentration of the H2SO4 solution, we need to use the balanced chemical equation for the neutralization reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4).
The balanced chemical equation for the reaction is:
2 KOH + H2SO4 → K2SO4 + 2 H2O
From the balanced equation, we can see that the stoichiometric ratio between KOH and H2SO4 is 2:1. This means that two moles of KOH react with one mole of H2SO4.
First, let's calculate the number of moles of KOH used in the reaction:
Moles of KOH = volume (in L) x concentration (in mol/L)
Moles of KOH = 0.02874 L x 0.500 mol/L
Moles of KOH = 0.01437 mol
Since the stoichiometric ratio is 2:1, the number of moles of H2SO4 is half of the moles of KOH used in the reaction:
Moles of H2SO4 = 0.01437 mol / 2
Moles of H2SO4 = 0.007185 mol
Now, let's calculate the concentration of the H2SO4 solution:
Concentration (in mol/L) = moles / volume (in L)
Concentration = 0.007185 mol / 0.05000 L
Concentration = 0.1437 mol/L
Therefore, the concentration of the H2SO4 solution is 0.1437 M.
To find the concentration of the H2SO4 solution, you can use the following steps:
Step 1: Write the balanced chemical equation for the acid-base neutralization reaction.
The balanced equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is:
2 KOH + H2SO4 -> K2SO4 + 2 H2O
Step 2: Determine the moles of KOH used.
To find the moles of KOH, you can use the formula:
moles = concentration (M) x volume (L)
Given:
- Volume of KOH solution (V1) = 28.74 mL = 28.74/1000 L = 0.02874 L
- Concentration of KOH solution (C1) = 0.500 M
Using the formula, moles of KOH (n1) = C1 x V1.
n1 = 0.500 M x 0.02874 L
Step 3: Use stoichiometry to determine the moles of H2SO4.
From the balanced equation, we can see that the molar ratio between KOH and H2SO4 is 2:1. Therefore, the moles of H2SO4 (n2) would be half the moles of KOH.
n2 = n1/2
Step 4: Calculate the concentration of the H2SO4 solution.
Given:
- Volume of H2SO4 solution (V2) = 50.00 mL = 50.00/1000 L = 0.05000 L
Using the formula, concentration of H2SO4 (C2) = n2/V2.
C2 = n2 / 0.05000 L
Now, substitute the value of n2 in the equation and calculate C2.
C2 = (n1/2) / 0.05000 L
Finally, you will have the concentration of the H2SO4 solution in M (mol/L).
Nb*Vb=Na*Va where N means normality
Na=NbVb/Va= .5N*28.74/50
but Na=2Ma
solve for Molarity of acid.