175g of water was heated fro 15 to 88 degrees C. how many kilocalories were absorbed by the water?
I got 94.5 kcal. Is this right?
I don't think so.
q = mass water x specific heat water x delta T.
q = 175g x 1 cal/g x (88-15) = 12,775 calories. Change to kcal.
12.775
175g of water was heated fro 15 to 88 degrees C. how many kilocalories were absorbed by the water?
Oh, what a heated situation we have here! Well, let's calculate it together. To determine the energy absorbed by the water, we need to use the specific heat capacity equation:
Energy = mass * specific heat capacity * change in temperature
Now, the specific heat capacity of water is approximately 4.186 joules per gram per degree Celsius. So, first, let's convert grams to kilograms because it's more fun that way.
175 grams = 0.175 kilograms
Now, plug in the values:
Energy = 0.175 kg * 4.186 J/g°C * (88°C - 15°C)
Calculating this gives us:
Energy = 0.175 kg * 4.186 J/g°C * 73°C
And now it's time for a grand finale! Thermostat, please!
Energy = 53.6795 kilojoules
You're in luck! You were close, but not quite there. To convert kilojoules to kilocalories, you need to divide the energy by 4.184:
53.6795 kJ / 4.184 = 12.834 kcal
That's the ticket! So, the correct answer is approximately 12.834 kilocalories. Keep up the scientific calculations, my friend!
To calculate the number of kilocalories absorbed by the water, you need to use the specific heat capacity of water. The specific heat capacity of water is 1 calorie/gram°C, or 1 kcal/kg°C.
First, calculate the change in temperature:
ΔT = final temperature - initial temperature
= 88°C - 15°C
= 73°C
Next, calculate the energy absorbed by the water using the formula:
Energy = mass × specific heat capacity × ΔT
mass of water = 175g
specific heat capacity of water = 1 kcal/kg°C
ΔT = 73°C
Energy = 175g × 1 kcal/kg°C × 73°C
= 12,775 kcal
So, according to the calculations, the water absorbed 12,775 kcal of energy. Therefore, your initial answer of 94.5 kcal is not correct.