Populations are frequently NOT in equilibrium due to selection or other evolutionary forces. Imagine a population of 100 individuals. Forty-nine of the individuals are homozygous dominant for beady-eye gene, 9 are heterozygous and 42 are homozygous recessive. NOTE: The population is NOT in equilibrium!! There are more homozygous recessive than you would predict by chance.

a. How many alleles are there in the population for ‘beady-eye gene.’ (Not just the dominant allele; all alleles for the gene – this is not a frequency or percentage – literally how many alleles are there?)
b. Howmanydominantallelesarethereinthegenepool?
(HINT: do not use Hardy-Weinberg equation – the population is not in equilibrium – you know the # of individuals of each genotype so figure out how many of each type of allele (dominant or recessive) that each person has and add them up).
c. How many recessive alleles are there in the gene pool?
d. Whatarethegenotypefrequencies(basedonthe#sabove,nottheHardy-Weinberg equilibrium)?

You just count:

a) all allele: 100*2
b) dominant: 49*2 + 9+1
c) 9*1+42*2

check those.

200

To answer these questions, we need to understand the concept of alleles and genotypes. Alleles are different forms of a gene, and genotypes refer to the combinations of alleles an individual has for a particular gene.

a. To determine the number of alleles in the population for the "beady-eye gene," we need to count the total number of alleles present in the 100 individuals. Since each individual has two alleles for this gene, we can calculate the total alleles by multiplying the number of individuals by 2:
Total alleles = 100 individuals * 2 alleles per individual = 200 alleles

b. To find the number of dominant alleles in the gene pool, we need to look at the individuals' genotypes. In this population, 49 individuals are homozygous dominant, and since each homozygous individual has two dominant alleles, we multiply the number of homozygous dominant individuals (49) by 2:
Dominant alleles = 49 homozygous dominant individuals * 2 alleles per individual = 98 dominant alleles

c. For the number of recessive alleles in the gene pool, we need to consider the homozygous recessive individuals. In this population, there are 42 homozygous recessive individuals, and since each homozygous individual also has two recessive alleles, we multiply the number of homozygous recessive individuals (42) by 2:
Recessive alleles = 42 homozygous recessive individuals * 2 alleles per individual = 84 recessive alleles

d. To determine the genotype frequencies, we divide the number of individuals with each genotype by the total number of individuals in the population and express the results as percentages.

Genotype frequencies:
- Homozygous dominant: 49 individuals / 100 individuals * 100% = 49%
- Heterozygous: 9 individuals / 100 individuals * 100% = 9%
- Homozygous recessive: 42 individuals / 100 individuals * 100% = 42%