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Using the values for the heat of fusion, specific heat of water, or heat of vaporization, calculate the amount of heat energy in each of the following:

* calories removed to condense 125g of steam at 100 degree C to cool the liquid to 15 degree C

* joules needed to melt a 525-g ice cube at 0 degree C and to war the liquid to 15 degree C

*Kilocalories removed to condense 85 g of steam at 100 degree C, cool the liquid to 0 degree C, and freeze it at 0 degree C

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3 answers
  1. First one.

    q1 = heat removed to condense 125 g steam at 100 C to water at 100 C.
    q1 = mass steam x heat vaporization.

    q2 = heat removed to cool liquid water at 100 C to 15 C.
    q2 = mass water x specific heat water x (Tfinal-Tinitial).

    qtotal = q1 + q2

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  2. 300

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  3. 500kl

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