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The concentration of a benzene solution prepared by mixing 12.0 g C6H6 with 38.0 g CCl4 is__________ molal.

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4 answers

  1. Thanks for the help, is this right?
    12.0/78.12=0.1536

    0.1536/0.038=4.04

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  2. moles C6H6 = grams/molar mass C6H6.

    m = moles C6H6/kg solvent.

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  3. Yup

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  4. sjvysg xbasbxjv

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