Compared to the Sun's gravitational force on the Earth, what is the Sun's gravitational force on Jupiter.

Jupiter's average distance from the Sun=5AU
Earth's average distance from the Sun=1AU

Jupiter's mass is 300 times larger than Earth.

I think the answer is 25 times weaker, but I am not positive.

(Jupiter gravity)/(Earth gravity) = 300/5^2 = 12 times stronger.

The greater mass of Jupiter outweighs the its distance from the sun

How did you come up wth 25 times less?

Of th following stars, which is brightest?nova,sun,white dwarf,red giant.

To determine the Sun's gravitational force on an object, we can use the formula:

F = G * (m1 * m2) / r^2

Where:
F is the gravitational force
G is the gravitational constant (approximately 6.674 x 10^-11 N * m^2 / kg^2)
m1 and m2 are the masses of the two objects
r is the distance between the centers of the two objects

In this case, we want to compare the Sun's gravitational force on the Earth to its force on Jupiter. Let's denote the force on the Earth as F_E and the force on Jupiter as F_J.

We know that the distance between the Sun and the Earth is 1 AU, while the distance between the Sun and Jupiter is 5 AU. Plugging these values into the formula, we get:

F_E = G * (m_Sun * m_Earth) / r_Earth^2
F_J = G * (m_Sun * m_Jupiter) / r_Jupiter^2

Since we are comparing the forces, we can divide these equations:

F_J / F_E = [G * (m_Sun * m_Jupiter) / r_Jupiter^2] / [G * (m_Sun * m_Earth) / r_Earth^2]

Simplifying and canceling out the common terms:
F_J / F_E = (m_Jupiter * r_Earth^2) / (m_Earth * r_Jupiter^2)

Now, let's substitute the given values:
m_Jupiter = 300 * m_Earth (Jupiter's mass is 300 times larger than Earth)
r_Earth = 1 AU
r_Jupiter = 5 AU

F_J / F_E = (300 * m_Earth * (1 AU)^2) / (m_Earth * (5 AU)^2)

Calculating the ratio of forces:
F_J / F_E = (300 * 1) / (1 * 25) = 12

Therefore, the Sun's gravitational force on Jupiter is 12 times stronger than its force on Earth.