If the same amount of heat is supplied to sample of 10.0g each aluminum, iron,and copper all at 15 degrees celsius which sample would reach the highest temperature????

The material with the lowest specific heat will have the largest temperature tise.

thanks :)

To determine which sample would reach the highest temperature when the same amount of heat is supplied, we need to consider the specific heat capacity of each material.

The specific heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius per gram. The formula for calculating heat energy is:

Q = m * c * ΔT

Where:
Q = heat energy
m = mass
c = specific heat capacity
ΔT = change in temperature

Let's find the final temperature for each material:

1. Aluminum:
The specific heat capacity of aluminum is 0.897 J/g°C.
The mass of the sample is 10.0 g.
The initial temperature is 15°C.

Q = m * c * ΔT
Q = 10.0 g * 0.897 J/g°C * ΔT
Q = 8.97 J/°C * ΔT

As we are supplying the same amount of heat energy to all the samples, the value of Q is constant. Therefore:

8.97 J/°C * ΔT_aluminum = 8.97 J/°C * ΔT_iron = 8.97 J/°C * ΔT_copper

2. Iron:
The specific heat capacity of iron is 0.450 J/g°C.
The mass of the sample is 10.0 g.
The initial temperature is 15°C.

Q = m * c * ΔT
Q = 10.0 g * 0.450 J/g°C * ΔT
Q = 4.50 J/°C * ΔT

3. Copper:
The specific heat capacity of copper is 0.385 J/g°C.
The mass of the sample is 10.0 g.
The initial temperature is 15°C.

Q = m * c * ΔT
Q = 10.0 g * 0.385 J/g°C * ΔT
Q = 3.85 J/°C * ΔT

Since Q is constant, we can set up the equation:

8.97 J/°C * ΔT_aluminum = 4.50 J/°C * ΔT_iron = 3.85 J/°C * ΔT_copper

To find the material that reaches the highest temperature, we need to compare the values of ΔT for each material. Since the values of Q and mass are the same for all materials, the one with the lowest specific heat capacity, c, will have the highest ΔT.

Comparing the specific heat capacities:
Aluminum: 0.897 J/g°C
Iron: 0.450 J/g°C
Copper: 0.385 J/g°C

Copper has the lowest specific heat capacity, so it will reach the highest temperature.

To determine which sample would reach the highest temperature, we need to consider the specific heat capacity of each material. The specific heat capacity is the amount of heat energy required to raise the temperature of a given substance by a certain amount.

Here is the formula to calculate the amount of heat energy:

Q = m * c * ΔT

Where:
Q = Heat energy (in joules)
m = Mass of the substance (in grams)
c = Specific heat capacity (in J/g°C)
ΔT = Change in temperature (in °C)

Since we are supplying the same amount of heat energy (Q) to each sample, we can assume that Q is constant. Therefore, we can calculate the final temperature of each sample by rearranging the formula:

ΔT = Q / (m * c)

Let's calculate the final temperature for each sample:

For aluminum:
m = 10.0 g
c(aluminum) = 0.897 J/g°C

ΔT(aluminum) = Q / (m * c(aluminum))

For iron:
m = 10.0 g
c(iron) = 0.450 J/g°C

ΔT(iron) = Q / (m * c(iron))

For copper:
m = 10.0 g
c(copper) = 0.385 J/g°C

ΔT(copper) = Q / (m * c(copper))

Since the same amount of heat is supplied to all samples, the sample with the highest specific heat capacity will experience the smallest change in temperature. Therefore, the sample with the highest specific heat capacity, which is aluminum (c = 0.897 J/g°C), will reach the highest final temperature.