For the equation:

NH4NO3 ==> N2O + 2H2O

how would I find how many grams of N2O are formed if 0.46mol NH4NO3?

Would I start out with
0.46mol NH4NO3 * ( / )

0.46 mol NH4NO3 * 1 mol N2O/1 mol NH4NO3

= 0.46 mol N2O
0.46 mol N2O * 43.99 g N2O/1 mol N2O
= 20.24 g N2O

Well, to find out how many grams of N2O are formed, we need to use the molar mass of N2O. Let's do some math:

The molar mass of NH4NO3 is approximately 80 grams/mol, and the molar mass of N2O is approximately 44 grams/mol.

So, first, let's convert the moles of NH4NO3 to moles of N2O. According to the balanced equation, for every 1 mole of NH4NO3, we get 1 mole of N2O.

0.46 mol NH4NO3 * (1 mol N2O / 1 mol NH4NO3) = 0.46 mol N2O

So, now we have 0.46 moles of N2O.

To convert moles into grams, we can use the molar mass of N2O:

0.46 mol N2O * (44 g N2O / 1 mol N2O) = 20.24 grams

Therefore, approximately 20.24 grams of N2O will be formed.

To find the number of grams of N2O formed, you need to use the mole ratio between NH4NO3 and N2O.

The balanced equation shows that 1 mol of NH4NO3 produces 1 mol of N2O.

So, you can set up a mole ratio as follows:

0.46 mol NH4NO3 * (1 mol N2O / 1 mol NH4NO3) * (molar mass of N2O / 1 mol N2O)

To calculate the molar mass of N2O, you need to look up the atomic masses of nitrogen (N) and oxygen (O) and multiply them by their respective subscripts in the formula N2O.

The molar mass of N2O turns out to be approximately 44 grams/mol.

Substituting the values into the equation:

0.46 mol NH4NO3 * (1 mol N2O / 1 mol NH4NO3) * (44 g N2O / 1 mol N2O)

Now, calculate the result:

0.46 mol NH4NO3 * (1 mol N2O / 1 mol NH4NO3) * (44 g N2O / 1 mol N2O) = 20.24 grams of N2O

Therefore, approximately 20.24 grams of N2O are formed when 0.46 mol of NH4NO3 reacts.

To find the number of grams of N2O formed when 0.46 mol of NH4NO3 reacts, you need to use the stoichiometry of the balanced equation.

The balanced equation shows that 1 mole of NH4NO3 produces 1 mole of N2O. Therefore, the ratio between the moles of NH4NO3 and N2O is 1:1.

Here's how you can calculate it:

1. Start with the given number of moles of NH4NO3: 0.46 mol NH4NO3.
2. Use the stoichiometric ratio of the equation to convert moles of NH4NO3 to moles of N2O. Since the ratio is 1:1, the number of moles of N2O will also be 0.46 mol.
3. Convert moles of N2O to grams by multiplying the number of moles by the molar mass of N2O. The molar mass of N2O is 44.02 g/mol.
Calculation: 0.46 mol N2O * 44.02 g/mol = 20.2 grams of N2O.

Therefore, when 0.46 mol of NH4NO3 reacts, 20.2 grams of N2O will be formed.