Zucchini cores placed in sucrose solutions at 27oC resulted in the following percent changes after 24 hours:

% change in mass [Sucrose]
20 distilled water
10 0.2 M
-3 0.4 M
-17 0.6 M
-25 0.8 M
-30 1.0 M

Graph the results and find the molar concentration of solutes within the zucchini cells. Calculate the solute potential of the sucrose solution in which the mass of the zucchini cores does not change. Calculate the water potential of the solutes within the zucchini cores.

-6.86 bars

Oh, I see we're getting scientific now! Let's tackle this one step at a time, shall we? First, let's graph the results:

Percent Change in Mass (%): [Sucrose Concentration (M)]
20 distilled water
10 0.2 M
-3 0.4 M
-17 0.6 M
-25 0.8 M
-30 1.0 M

Now, let's move on to finding the molar concentration of solutes within the zucchini cells. It seems like at a sucrose concentration of 0.2 M, we have a percent change of 10. So, we can infer that the molar concentration of solutes within the zucchini cells is approximately 0.2 M.

Next, we need to calculate the solute potential of the sucrose solution in which the mass of the zucchini cores does not change. The solute potential is the measure of the tendency of water to move from a less concentrated solution to a more concentrated one. So, when the mass of the zucchini cores does not change, it means there is no net movement of water. In this case, the solute potential of the sucrose solution is equal to the water potential of the zucchini cores.

Finally, let's calculate the water potential of the solutes within the zucchini cores. In order to do this, we need to convert the percent change in mass to a decimal and plug it into the formula:

Water Potential (Ψ) = Solute Potential (Ψs) + Pressure Potential (Ψp)

Since the water potential is zero when the mass does not change, the solute potential (Ψs) must be equal in magnitude but opposite in sign to the pressure potential (Ψp). Therefore, the water potential is zero when the mass of the zucchini cores does not change.

I hope this helps! If you have any more questions, feel free to ask!

To accurately graph the results and analyze the molar concentration of solutes within the zucchini cells, we can plot the percent change in mass (% change) against the molar concentration of sucrose ([Sucrose]).

First, let's create a table to organize the given data:

[Sucrose] (M) % change in mass
0 (distilled water) 20
0.2 10
0.4 -3
0.6 -17
0.8 -25
1.0 -30

Now let's create a graph using this data. The x-axis represents the molar concentration of sucrose ([Sucrose]) and the y-axis represents the percent change in mass (% change). We will start by labeling the axes:

X-axis: [Sucrose] (M)
Y-axis: % change in mass

Next, plot the data points on the graph:

Data point 1: [Sucrose] = 0 M, % change = 20
Data point 2: [Sucrose] = 0.2 M, % change = 10
Data point 3: [Sucrose] = 0.4 M, % change = -3
Data point 4: [Sucrose] = 0.6 M, % change = -17
Data point 5: [Sucrose] = 0.8 M, % change = -25
Data point 6: [Sucrose] = 1.0 M, % change = -30

Join the data points with a smooth curve to represent the trend. The graph will show a decreasing trend as the molar concentration of sucrose increases.

To find the molar concentration of solutes within the zucchini cells, we need to locate the point on the graph where the percent change in mass is zero. From the graph, it appears that this occurs between the [Sucrose] of 0.4 M and 0.6 M. To obtain a more accurate value, we can interpolate between these two points. Let's calculate the concentration:

% change at 0.4 M: -3
% change at 0.6 M: -17

Using the formula:

[Solute] = ([Sucrose2] - [Sucrose1]) * (% change - % change1) / (% change2 - % change1) + [Sucrose1]

[Solute] = (0.6 - 0.4) * (0 - (-3)) / ((-17) - (-3)) + 0.4

[Solute] = 0.2 * 3 / (-14) + 0.4

[Solute] = 0.6 / (-14) + 0.4

[Solute] = -0.04286 + 0.4

[Solute] = 0.35714 M

Therefore, the molar concentration of solutes within the zucchini cells is approximately 0.35714 M.

To calculate the solute potential of the sucrose solution in which the mass of the zucchini cores does not change, we use the formula:

Ψs = -iCRT

Where:
Ψs = solute potential
i = ionization constant (assume 1 for sucrose)
C = molar concentration of sucrose (0.35714 M)
R = pressure constant (0.0831 L bar mol^−1 K^−1)
T = temperature in Kelvin (27 + 273 = 300 K)

Let's calculate the solute potential Ψs:

Ψs = -1 * 0.35714 M * 0.0831 L bar mol^−1 K^−1 * 300 K

Ψs = -8.436 L bar mol^−1

Therefore, the solute potential of the sucrose solution in which the mass of the zucchini cores does not change is approximately -8.436 L bar mol^−1.

Finally, to calculate the water potential of the solutes within the zucchini cores, we need to use the formula:

Ψw = Ψs + Ψp

Where:
Ψw = water potential
Ψs = solute potential (-8.436 L bar mol^−1)
Ψp = pressure potential (assumed to be 0 since it was not given)

Let's calculate the water potential Ψw:

Ψw = -8.436 L bar mol^−1 + 0

Ψw = -8.436 L bar mol^−1

Therefore, the water potential of the solutes within the zucchini cores is approximately -8.436 L bar mol^−1.

To graph the results, we will plot the percent change in mass of the zucchini cores on the y-axis and the molar concentration of the sucrose solutions on the x-axis.

Using the given data, we can plot the points on a graph:

```
Percent Change in Mass | Molar Concentration (Sucrose)
20% | 0 (Distilled Water)
10% | 0.2 M
-3% | 0.4 M
-17% | 0.6 M
-25% | 0.8 M
-30% | 1.0 M
```

Now, let's plot these points on a coordinate plane, where the x-axis represents the molar concentration of sucrose and the y-axis represents the percent change in mass of the zucchini cores. By connecting these points with a line, we can determine the pattern in the data.

After plotting the points and connecting them, we can observe that the line decreases in a linear fashion as the molar concentration of sucrose increases.

To find the molar concentration of solutes within the zucchini cells, we need to identify the concentration value at which the mass of the zucchini cores does not change. Looking at the graph, we can see that the point where the line intersects the x-axis (y=0) is approximately 0.5 M.

Therefore, the molar concentration of solutes within the zucchini cells is approximately 0.5 M.

To calculate the solute potential of the sucrose solution in which the mass of the zucchini cores does not change, we can use the formula:

```
Ψ = -iCRT
```

Where:
- Ψ is the solute potential,
- i is the ionization constant (assume 1 for sucrose),
- C is the molar concentration of the solution, and
- R is the pressure constant (0.0831 L·bar·mol^−1·K^−1),
- and T is the temperature in Kelvin (27°C = 300 K).

Plugging in the values:

```
i = 1
C = 0.5 M
R = 0.0831 L·bar·mol^−1·K^−1
T = 300 K
```

We can now calculate the solute potential:

```
Ψ = - (1)(0.5)(0.0831)(300)
= -12.465 L·bar·mol^-1·K^-1
```

Therefore, the solute potential of the sucrose solution in which the mass of the zucchini cores does not change is approximately -12.465 L·bar·mol^-1·K^-1.

Finally, to calculate the water potential of the solutes within the zucchini cores, we can use the formula:

```
Ψ = Ψ_solute
```

Since the solute potential (Ψ_solute) is given as -12.465 L·bar·mol^-1·K^-1, the water potential of the solutes within the zucchini cores is also -12.465 L·bar·mol^-1·K^-1.