what mass of a 15% (m/m) NaOH solution contains 125 grams NaOH?

833g

(mass NaOH/mass soln)*100 = percent

(125 g/x)*100 = 15
Solve for x.

To find the mass of a 15% (m/m) NaOH solution that contains 125 grams of NaOH, we can use a simple formula.

Step 1: Remember that percent (m/m) means grams of solute per 100 grams of solution.

Step 2: Let's assume the mass of the solution is "x".

Step 3: We know that 15% of the solution mass (x) is NaOH, which is equal to 125 grams.

Step 4: Set up the equation: 15/100 * x = 125.

Step 5: Simplify the equation: 0.15 * x = 125.

Step 6: Divide both sides of the equation by 0.15 to isolate x: x = 125 / 0.15.

Step 7: Calculate the value of x: x = 833.33 grams.

Therefore, a 15% (m/m) NaOH solution that contains 125 grams of NaOH has a mass of approximately 833.33 grams.

To find the mass of a 15% (m/m) NaOH solution that contains 125 grams of NaOH, we need to use the definition of mass/mass percent concentration.

The mass/mass percent concentration is calculated by dividing the mass of the solute (NaOH) by the mass of the solution and then multiplying by 100.

Let's assume the mass of the solution is "x" grams.

Mass percent = (Mass of solute / Mass of solution) * 100

15% = (125 grams / x grams) * 100

Now, cross-multiply and solve for x.

15 * x = 125 * 100

x = (125 * 100) / 15

x = 833.33 grams

Therefore, a 15% (m/m) NaOH solution containing 125 grams of NaOH has a mass of approximately 833.33 grams.