the length of a rectangle is half the width. The perimeter is 86 ft find the width of the rectangle
Length = L Ft.
Width = 2L Ft.
P = 2L + 4L = 86.
L = 14.33 Ft.
2L = 2 * 14.33 = 28.66 Ft = Width.
The length of a rectangle is one inch less than twice its width. The diagonal of the rectangle is two inches more than its length. Find the area of the rectangle
Let's assign variables to the width and length of the rectangle.
Let the width be W.
According to the given information, the length of the rectangle is half the width, so the length can be represented as L = 0.5W.
The perimeter of a rectangle is given by the formula: perimeter = 2(length + width).
Therefore, the equation for the perimeter can be written as:
86 = 2(0.5W + W)
Now, let's solve the equation to find the value of W:
86 = 2(1.5W)
86 = 3W
Dividing both sides of the equation by 3:
W = 86 / 3
W ≈ 28.67
So, the approximate width of the rectangle is 28.67 ft.
To find the width of the rectangle, we need to set up an equation based on the information given.
Let's assume that the width of the rectangle is represented by 'x'.
According to the information given, the length is half the width, so the length would be (1/2)x.
The perimeter of a rectangle is calculated by adding all four sides together. In this case, the perimeter is given as 86 ft, which can be expressed as:
Perimeter = 2(Length + Width)
Substituting the given information, we get:
86 = 2((1/2)x + x)
Simplifying further:
86 = 2(3/2)x
Dividing both sides of the equation by 2:
43 = (3/2)x
To remove the fraction, we can multiply both sides of the equation by 2/3:
(2/3) * 43 = x
Thus, the width of the rectangle is:
x = 28.67 ft (rounded to two decimal places)
Therefore, the width of the rectangle is approximately 28.67 feet.