how many grams of 5%NaNO3 will be required to prepare 250ml solution

To determine the amount of NaNO3 needed to prepare a 250 ml solution with a concentration of 5%, you need to follow these steps:

Step 1: Convert the desired volume from milliliters (ml) to liters (L).
Since 1 L is equal to 1000 ml, divide 250 ml by 1000 to get 0.25 L.

Step 2: Calculate the amount of NaNO3 needed using the formula:
Amount (g) = Volume (L) x Concentration (%)

Amount (g) = 0.25 L x 5%

Step 3: Convert the concentration from percentage to a decimal:
5% = 5/100 = 0.05

Amount (g) = 0.25 L x 0.05

Step 4: Multiply the volume and concentration to find the amount of NaNO3 needed:
Amount (g) = 0.25 L x 0.05 = 0.0125 g

Therefore, you will require 0.0125 grams of NaNO3 to prepare a 250 ml solution with a concentration of 5%.

To calculate the number of grams of 5% NaNO3 needed to prepare a 250 ml solution, we need to use the formula:

Amount (g) = (Concentration (%) * Volume (ml)) / 100

In this case, the concentration is 5% and the volume is 250 ml. Let's calculate it:

Amount (g) = (5 * 250) / 100
Amount (g) = 1250 / 100
Amount (g) = 12.5 g

Therefore, 12.5 grams of 5% NaNO3 will be required to prepare a 250 ml solution.

What kind of percent? Is this w/v, w/w, of just what. I will assume it is 5% w/v which means 5 g NaNO3/100 mL soln; therefore, for 250 mL (2.5 x 100) you will need 2.5 x 5 or 12.5 g NaNO3.