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two figure skaters, one weighting 625N and the other 725N,push off against each other on frictionless ice. a) if the heavest skater travels at 1.50m/s, how fast will the lighter one travel? b)how much kinetic energy is created during the skaters manauver, and where does this energy come from?

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kris-
2 answers

  1. a) The net momentum will remain zero. They will leave in opposite drections.
    (725/g)kg* 1.50m/s + (625/g)V = 0

    V is the speed of the ligther skater. Solve for it. The acceleration of gravity (g) can be cancelled out.

    V = -(725/625)*1.50 m/s

    The minus sign denotes going in the opposite direction.

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    drwls

  2. 1.74 m/s

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    dave

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