A 3.0 kg block being pulled across a table by a horizontal force of 80 N also experiences a frictional force of 5 N. What is the acceleration of the block?
a = F(net)/M = (80 - 5)/M
= 75/3 = 25 m/s^2
f1= 80N ; f2=5N
F=f1 - f2 = 80N - 5N= 75N
F=M*a
a= F/M =75N/3kg =25 m/s^2
a=25 m/s^2
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Now, let's solve the problem. To find the acceleration of the block, we need to apply Newton's second law, which states that F = ma, where F is the net force acting on the object, m is the mass of the object, and a is the acceleration.
In this case, the net force acting on the block is the difference between the applied force and the frictional force. So, Fnet = 80 N - 5 N = 75 N.
Using Newton's second law, we can rewrite it as a = Fnet / m. Plugging in the values, we get a = 75 N / 3.0 kg ≈ 25 m/s².
So, the acceleration of the block is approximately 25 m/s².
To find the acceleration of the block, we need to apply Newton's second law, which states that the net force is equal to the mass of an object multiplied by its acceleration:
Net force = mass * acceleration
In this case, the net force is the difference between the applied force and the frictional force:
Net force = Applied force - Frictional force
The mass of the block is given as 3.0 kg, the applied force is 80 N, and the frictional force is 5 N.
So, the net force is:
Net force = 80 N - 5 N = 75 N
Now, we can use Newton's second law to find the acceleration:
75 N = 3.0 kg * acceleration
Dividing both sides of the equation by 3.0 kg, we get:
acceleration = 75 N / 3.0 kg = 25 m/s^2
Therefore, the acceleration of the block is 25 m/s^2.
To find the acceleration of the block, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
First, let's find the net force acting on the block. The net force is the difference between the applied force and the frictional force. In this case, the applied force is 80 N, and the frictional force is 5 N.
Net force = Applied force - Frictional force
Net force = 80 N - 5 N
Net force = 75 N
Now, we can use Newton's second law to find the acceleration. Rearranging the formula, we have:
Acceleration = Net force / Mass
The mass of the block is given as 3.0 kg.
Acceleration = 75 N / 3.0 kg
Acceleration ≈ 25 m/s^2
So, the acceleration of the block is approximately 25 m/s^2.