1. Suppose that the strength of the electric field about an isolated point charge has a certain value at a distance of 1 m. How will the electric field strength compare at a distance of 2 m from the point charge?
I know it's At twice the distance the field strength will be 1/4 but what law applies here?
(Boyle's law, the universal law of electrical force, Coloumb's law or the inverse-square law)
the inverse-square law
Coulomb's Law is one of many inverse-square laws.
The law that applies in this scenario is the inverse-square law. According to the inverse-square law, the strength of the electric field decreases with the square of the distance from an isolated point charge. In this case, since the distance is doubled from 1 m to 2 m, the electric field strength will be 1/4 (or one-fourth) of the original value.
The law that applies in this scenario is the inverse-square law. According to the inverse-square law, the strength of the electric field around an isolated point charge decreases as the square of the distance from the charge increases.
In this case, the distance from the point charge is doubling from 1m to 2m. Using the inverse-square law, we can determine the ratio of the electric field strengths.
The inverse-square law states that the electric field strength is inversely proportional to the square of the distance. So, if the initial field strength at 1m is 100 units (just as an example), the field strength at 2m would be:
Field strength at 1m / Field strength at 2m = (1m / 2m)^2
= (1/2)^2
= 1/4
Therefore, at a distance of 2m from the point charge, the electric field strength will be 1/4th (or 25%) of the strength at a distance of 1m.
Hence, it is the inverse-square law that applies in this scenario.