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Hi, need a bit of help on this one.

A straight line passes through the points (4,3) and (10,0), I need to write down the equation of the line in the form y=mx+c, I have tried but I cant seem to get the second coordinates to satisfy the equation. Here is what I have done so far.

Found the gradient = -.5
Equation= y=-.5x+c
Substituted points 4,3 into equation= 3=-.5x4+c = 3=-2+c
Added 2 to both sides to give 5=c
Equation =y=-2+5

If I substitute points 10,0 into the equation I end up with y=-.5x10+5 = -15!

Where am I going wrong please?

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2 answers
  1. m = (0-3)/10-4) = 3/6 = POSITIVE 0.5

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  2. m = (0-3)/10-4) = -3/6 = - 0.5
    3 = -.5(4) + b
    3 = -2 + b
    b = 5
    so
    y = -0.5 x + 5

    try (10,0)
    0 = -0.5(10) + 5
    0 = -5 + 5 Yes, checks

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