Craft an image that captures the essence of electrostatic forces. In the scene, illustrate two spheres representing the charged particles, one with a negative symbol and the other with a positive symbol. Place the negative sphere on the left, and the positive one on the right. These spheres should be in a space setting, showing clear distinction in the charge of each sphere. Together with this, incorporate arrows suggesting the direction of electrostatic force between them. Note, the image should not contain any text or numbers.

A -4.0-µC charge is located 0.30 m to the left of a +6.0-µC charge. What is the magnitude and direction of the electrostatic force on the positive charge?

F = k q1*q2/R^2

F = 9x10^9((4*10^-6)(6*10^-6)/0.3^2)

F = 2.4 N to the left

Well, I have to admit, these charges seem like they're having a really shocking day! Let me calculate the magnitude and direction of the electrostatic force between them.

First of all, we need to use Coulomb's Law, which states that the magnitude of the electrostatic force between two charges is given by:

F = k * (|q1| * |q2|) / r^2

Here, k is the electrostatic constant, |q1| and |q2| are the magnitudes of the charges, and r is the distance between them.

Plugging in the values:
k = 8.99 * 10^9 N·m^2/C^2
|q1| = 4.0 * 10^-6 C
|q2| = 6.0 * 10^-6 C
r = 0.30 m

Calculating:
F = (8.99 * 10^9 N·m^2/C^2) * (4.0 * 10^-6 C * 6.0 * 10^-6 C) / (0.30 m)^2

After crunching the numbers, the result is approximately 2.39 N.

Now, as for the direction of the force, since the charges have opposite signs, they will attract each other. The force will be directed from the negative charge (left) towards the positive charge (right).

So, to sum it up, the magnitude of the electrostatic force is approximately 2.39 N, and its direction is from left to right. These charges are definitely not clowning around when it comes to their attraction!

To find the magnitude and direction of the electrostatic force between the two charges, we can use Coulomb's law formula:

F = k * (|q1| * |q2|) / r^2

where F is the electrostatic force, k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.

In this case, the magnitudes of the charges are |q1| = 4.0 x 10^-6 C and |q2| = 6.0 x 10^-6 C, and the distance between them is r = 0.30 m.

Plugging these values into the formula, we have:

F = (8.99 x 10^9 N m^2/C^2) * ((4.0 x 10^-6 C) * (6.0 x 10^-6 C)) / (0.30 m)^2

Simplifying, we get:

F = (8.99 x 10^9 N m^2/C^2) * (24 x 10^-12 C^2) / (0.09 m^2)

F = (8.99 x 24 x 10^-3 N) / (0.09 m^2)

F = 215.24 x 10^-3 N

Therefore, the magnitude of the electrostatic force on the positive charge is 215.24 x 10^-3 N.

To determine the direction, we need to consider the charges' polarities. The positive charge will experience a force towards the negative charge, in the direction away from the negative charge. Therefore, the direction of the electrostatic force on the positive charge is to the left.

The charges attract each other, so the force on the positive charge is to the left. Use Coulomb's law for the magnitude.

F = k q1*q2/R^2

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