A Stubborn, 120 kg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around the pulls with his maximum force of 800N. The coefficients of friction between the mule and the ground are Us=0.8 and Uk=0.5. Is the farmer able to move the mule?
He can move the mule if he can overcome the static friction force
M g * Us
How big is that?
No
A stubborn 100 kg mule sit down and refuse to move. To drag the mule the barn the exasperated former ties a rope around the mule and pulls with maximum force of 850 N the coefficient friction between mule and ground is o. 8 and k is 0.55
Is former able to move the mule?
To determine if the farmer is able to move the mule, we need to compare the force applied by the farmer to the maximum force of static (Us) or kinetic (Uk) friction acting on the mule.
The force of static friction (Fs) can be calculated using the formula:
Fs = Us * Normal Force
The normal force (N) is the force exerted by the surface on the mule perpendicular to the surface. In this case, it would be equal to the weight of the mule, which can be calculated using the formula:
Weight = mass * gravity
Given that the mass of the mule is 120 kg and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight of the mule:
Weight = 120 kg * 9.8 m/s² = 1176 N
Now we can calculate the force of static friction:
Fs = 0.8 * 1176 N = 940.8 N
Since the force applied by the farmer is 800 N, which is less than the force of static friction (940.8 N), the mule will not move. The maximum force the farmer can exert is not enough to overcome the static friction between the mule and the ground.
Therefore, the farmer is not able to move the mule using his maximum force of 800 N.