howdy, just cant seem to get this question, can anyone express this question in words i can get?! thanks
A sound wave of wavelength 0.8 m divides into two equal parts that recombine to interfere constructively, with the original difference between their path lengths being |r2|-|r1| = 0.8 m. Rank the following situations according to the intensity of sound at the receiver from the highest to the lowest. Assume the tube walls absorb no sound energy.
*The figure is two U shaped pipes with them shaped like opposite horseshoes, and at the junctions where they meet are holes for the sounding device and the other for the listener
Howdy! Sounds like you're having trouble understanding a question about sound waves and interference. Let's see if I can explain it in a way that's easier to understand, y'all!
Imagine you have two U-shaped pipes, kind of like opposite horseshoes. There's a hole at one end where the sound is being made, and another hole at the other end where the sound is being listened to.
Now, a sound wave with a wavelength of 0.8 meters is traveling through these pipes. It splits into two equal parts, but they eventually come back together and interfere constructively, meaning they combine to make a louder sound.
The question wants you to rank different scenarios based on the intensity of the sound at the listener's end, from highest to lowest. Keep in mind that the walls of the pipes don't absorb any sound energy.
I hope that helps clarify things for you! If you have any more questions, feel free to ask.
The question asks you to rank different situations based on the intensity of sound at the receiver.
The situation involves a sound wave of wavelength 0.8 m that divides into two equal parts and then recombines to interfere constructively. The original difference between the path lengths of these two parts is given as |r2| - |r1| = 0.8 m.
You are asked to rank the situations from highest to lowest intensity of sound at the receiver. The figure mentioned in the question shows two U-shaped pipes, shaped like opposite horseshoes, with holes at the junctions for the sounding device and the listener. The tube walls do not absorb any sound energy.
To solve this, you need to consider how the interference of the sound waves affects the intensity at the receiver. Interference can result in constructive or destructive interference, depending on the path length difference between the waves. Constructive interference leads to higher intensity, while destructive interference leads to lower intensity.
You need to analyze the different scenarios presented and determine how the sound waves interfere in each case. Then, rank the scenarios from highest to lowest intensity based on this analysis.
Sure! I can help you with that. To rank the situations according to the intensity of sound at the receiver, we need to consider the interference of the sound waves.
First, let's understand what the given information is telling us. We have a sound wave with a wavelength of 0.8 m, and it divides into two equal parts. When these two parts recombine, they interfere constructively.
The original difference between their path lengths is given as |r2| - |r1| = 0.8 m. Here, |r2| represents the path length of the second part of the sound wave, and |r1| represents the path length of the first part of the sound wave.
Now, let's analyze the situations and rank them from highest to lowest sound intensity at the receiver:
1. Situation with both pipes having the same length:
If both pipes have exactly the same length, the path lengths for both parts of the sound wave will be equal. Therefore, the interference will be constructive, and the sound will have the highest intensity at the receiver.
2. Situation with one pipe longer than the other:
If one pipe is longer than the other, the path lengths for the two parts of the sound wave will be different. However, we know that |r2| - |r1| = 0.8 m. With one pipe longer than the other, the difference in path lengths will be exactly 0.8 m, resulting in constructive interference and a high sound intensity at the receiver.
3. Situation with both pipes having lengths that differ from each other by a value other than 0.8 m:
If both pipes have lengths that differ from each other by a value other than 0.8 m, the difference in path lengths will not match the original difference of 0.8 m. This will lead to some degree of destructive interference, reducing the sound intensity at the receiver. Therefore, this situation will have a lower sound intensity compared to the previous two situations.
Remember, in all these situations, we assume that the walls of the tubes absorb no sound energy.
So, to summarize the ranking from the highest to the lowest sound intensity at the receiver:
1. Situation with both pipes having the same length
2. Situation with one pipe longer than the other
3. Situation with both pipes having lengths that differ from each other by a value other than 0.8 m
a. If the tube is moved by 0.1 m, r2 increases by 0.2m, so r2-r1 is now 0.1m. Therefore lambda is (2pi/0.8)(0.1)=2.5pi
--> Intensity=I cos squared(2.5pi/2)
You pretty much d that for each one and you get d>a=c>b