2NO(g) + O2(g) -> 2NO2(g)
In one experiment 0.886 moles of NO is mixed with 0.503 moles of O2.
Calculate which of the two reactants is the limiting reagent.
Please show set up of problem and show work.
YOu need two moles of NO for each mole of O2. The mole ratio is .886/.503, which is less than 2, which means there is not enough NO. So NO is the limiting reagent.
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