Two cars are driving toward each other on a straight, flat Kansas road. The Jeep Wrangler is traveling at 84 km/h north and the Ford Taurus is traveling at 43 km/h south, both measured relative to the road. What is the velocity of the Jeep relative to an observer in the Ford?
Vjf= 84+43 km/hr South. Think on that.
what does Vjf stand for?
84-43km/h= 41km/h because north is in quadrant one which means it is positive however west is in quadrant four which means it is negative.
To find the velocity of the Jeep relative to an observer in the Ford, we need to add the velocities of the Jeep and the Ford since they are moving in opposite directions.
The velocity of the Jeep Wrangler is 84 km/h north, and the velocity of the Ford Taurus is 43 km/h south. Since north and south are opposite directions, we need to consider one of the velocities as negative.
Let's assign the north direction as positive and the south direction as negative.
The velocity of the Jeep relative to an observer in the Ford can be calculated by adding the velocities. Since the Jeep is going north and the Ford is going south, we subtract the velocity of the Ford from the velocity of the Jeep:
Velocity of Jeep relative to Ford = Velocity of Jeep - Velocity of Ford
Velocity of Jeep relative to Ford = 84 km/h - (-43 km/h)
When subtracting a negative number, it is the same as adding the positive number. Therefore:
Velocity of Jeep relative to Ford = 84 km/h + 43 km/h
Simplifying, we get:
Velocity of Jeep relative to Ford = 127 km/h
So, the velocity of the Jeep relative to an observer in the Ford is 127 km/h.