Ask questions and get helpful answers.

In a survey of 1037 adults, ages 65 and over, 643 were concerned about getting the flu.

a) Find the point estimate for the population proportion , p , of those concerned about getting the flu.

b) Construct a 90% Confidence Interval for the population proportion.

c) How big a sample size would be needed to allow for a 2% margin of error?

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

2 answers

  1. Use a proportional confidence interval formula.

    CI90 = p + or - (z-value)(√ pq/n)
    Find z-value using a z-table representing 90%. p = 643/1037 (convert to a decimal). q = 1 - p. n = 1037 (sample size). Plug values into the formula and calculate the interval.

    Formula to find sample size:
    n = [(z-value)^2 * p * q]/E^2
    ... where n = sample size, z-value is the same as above, p and q are the same as above, ^2 means squared, * means to multiply, and E = .02 (for 2%).
    Plug values into the formula and calculate n.

    I hope this will help get you started.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. the only thing this is, is useless

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.