Sulfur trioxide is made from the reaction of sulfur dioxide and oxygen. how many grams of SO3 can be made from the reaction of 1.91g SO2 with 1.29g O2?
2 SO2(g) + O2(g)---> 2SO3(g)
a) 2.39g
b) 3.20g
c) 3.23g
d) 4.77g
e) 6.46g
How would i solve this problem?? Im thinking i would use the simplest formula, but im not sure if that's right. And if so, how would i do it??
This is a limiting reagent problem.
1. You have the equation and it's balanced.
2a. Convert 1.91 g SO2 to moles. moles = grams/molar mass.
2b. Convert 1.92 g O2 to moles. Same procedure.
3a. Using the coefficients in the balanced equation, convert moles of SO2 (from 2a) to moles of SO3.
3b. Same process, convert moles O2 (from 2b) to moles SO3.
3c. Probably the moles from 3a and 3b will be different which means one of them is wrong. The correct number of moles, in limiting reagent problems, is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
4. Convert moles from 3c to grams. g = moles x molar mass.
To solve this problem, you will need to use stoichiometry and the concept of limiting reactants.
1. Start by writing out the balanced equation:
2 SO2(g) + O2(g) ---> 2 SO3(g)
2. Calculate the number of moles of each reactant:
Moles of SO2 = mass of SO2 / molar mass of SO2
Moles of SO2 = 1.91 g / 64.06 g/mol = 0.0299 mol
Moles of O2 = mass of O2 / molar mass of O2
Moles of O2 = 1.29 g / 32.00 g/mol = 0.0403 mol
3. Determine the limiting reactant:
To find the limiting reactant, compare the moles of each reactant to the stoichiometric ratio in the balanced equation. The reactant that produces the least number of moles of SO3 will be the limiting reactant.
According to the balanced equation, 2 moles of SO2 react with 1 mole of O2 to produce 2 moles of SO3.
Ratio of moles of SO2 to SO3 = 0.0299 mol SO2 / 2 mol SO3 = 0.01495 mol SO3
Ratio of moles of O2 to SO3 = 0.0403 mol O2 / 1 mol SO3 = 0.0403 mol SO3
The ratio for SO2 is smaller, indicating that SO2 is the limiting reactant.
4. Calculate the moles of SO3 formed:
To calculate the moles of SO3 formed, use the stoichiometry from the balanced equation:
Moles of SO3 = moles of limiting reactant x stoichiometric ratio
Moles of SO3 = 0.0299 mol SO2 x (2 mol SO3 / 2 mol SO2) = 0.0299 mol SO3
5. Convert moles of SO3 to grams:
Mass of SO3 = moles of SO3 x molar mass of SO3
Mass of SO3 = 0.0299 mol x 80.06 g/mol = 2.39 g
Therefore, the answer is Option (a) 2.39g.
To solve this problem, you can use stoichiometry, which is a method that relates the moles of reactants and products in a chemical equation. Here's how you can approach this:
Step 1: Write down the balanced chemical equation:
2 SO2(g) + O2(g) -> 2 SO3(g)
Step 2: Convert the given masses of SO2 and O2 into moles. You'll need to use the molar masses of these substances, which can be found on the periodic table.
Molar mass of SO2 = 32.06 g/mol
Molar mass of O2 = 31.9988 g/mol
Moles of SO2 = mass of SO2 / molar mass of SO2
Moles of SO2 = 1.91 g / 32.06 g/mol
Moles of O2 = mass of O2 / molar mass of O2
Moles of O2 = 1.29 g / 31.9988 g/mol
Step 3: Determine the limiting reactant. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed. To do this, you need to compare the mole ratios of the reactants, which are given by the coefficients in the balanced chemical equation.
In this case, you need to calculate the moles of SO3 formed from the moles of each reactant using the mole ratio from the balanced equation:
From 2 moles of SO2, 2 moles of SO3 are formed
From 1 mole of O2, 2 moles of SO3 are formed
Step 4: Calculate the moles of SO3 formed from each reactant:
Moles of SO3 formed from SO2 = moles of SO2 x (2 moles of SO3 / 2 moles of SO2)
Moles of SO3 formed from O2 = moles of O2 x (2 moles of SO3 / 1 mole of O2)
Step 5: Identify the limiting reactant. The reactant that produces fewer moles of SO3 is the limiting reactant. The amount of product formed will be based on the moles of the limiting reactant.
Step 6: Calculate the moles of SO3 formed from the limiting reactant.
Step 7: Convert the moles of SO3 to grams:
Grams of SO3 = moles of SO3 formed x molar mass of SO3
Step 8: Compare the calculated grams of SO3 to the given answer choices and choose the closest match.
By following these steps and performing the necessary calculations, you should be able to determine the correct answer.