# A ladder 14 ft long rests against a vertical wall. Let \theta be the angle between the top of the ladder and the wall and let x be the distance from the bottom of the ladder to the wall. If the bottom of the ladder slides away from the wall, how fast does x change with respect to \theta when \theta = \pi / 3?

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1. sinØ = x/14

cosØ = (1/4)dx/dØ
dx/dØ = 4cosØ

so when Ø = π/3
dx/dØ = 4cosπ/3 = 2

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2. somehow my 14 changed to 4,
(need new specks)

so all the 4's are 14's
and last line is
dx/dØ = 14cos π/3 = 7

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