A bag contains 7 red marbles, 2 blue marbles, and 1 green marble. If a marble is selected at random,
what is the probability of choosing a marble that is not blue?
7 red marbles plus 1 green marble = 8/10 = answer = 4/5
A box contains 10 marbles, five blue, four white and one red. two marbles are picked at random (neither are replaced) what is the probability that neither marble is blue
P(red)
If John has 22 marbles and 25 are reds, 16 are blue and the remaining marbles are yellow, what percentages of John’s marbles are yellow?
To find the probability of choosing a marble that is not blue, we need to determine the total number of marbles that are not blue, and then divide it by the total number of marbles in the bag.
In this case, the total number of marbles that are not blue is the sum of the red marbles (7) and the green marble (1), which equals 8 marbles.
The total number of marbles in the bag is the sum of all the marbles, which is 7 (red) + 2 (blue) + 1 (green) = 10 marbles.
Therefore, the probability of choosing a marble that is not blue is 8/10, which can be simplified to 4/5.