When a single card is drawn from an ordinary 52-card deck, find the odds in favor of getting a red 10 or a black 6.

I think the answer is 1:12. Is that correct?

There are 2 red tens and 2 black sixes.

Therefore 4/52 = 1/13

To find the odds in favor of getting a red 10 or a black 6 when drawing a single card from a standard 52-card deck, we need to determine the number of favorable outcomes and the number of possible outcomes.

First, let's count the favorable outcomes:
- There are two red tens in the deck (hearts and diamonds).
- There is one black six in the deck (clubs).
So, the number of favorable outcomes is 2 (red tens) + 1 (black six) = 3.

Next, let's count the total number of possible outcomes:
- A standard deck has a total of 52 cards.

Therefore, the odds in favor of getting a red 10 or a black 6 are 3 favorable outcomes out of 52 possible outcomes.

In fraction form, the odds in favor are 3/52. In ratio form, they can be simplified to 1/17.

So, the correct answer is 1:17, not 1:12.

To find the odds in favor of getting a red 10 or a black 6 from an ordinary 52-card deck, we need to determine the number of favorable outcomes (red 10 or black 6) and the number of possible outcomes (all cards in the deck).

There are two red 10s in the deck: the 10 of hearts and the 10 of diamonds. There are also two black 6s in the deck: the 6 of clubs and the 6 of spades. Therefore, we have a total of four favorable outcomes.

Since there are 52 cards in a deck, the number of possible outcomes is 52.

To find the odds in favor, we can express it as a ratio of favorable outcomes to the remaining possible outcomes. In this case, it would be 4:48, which simplifies to 1:12.

So, your answer of 1:12 is correct.