An object with an initial speed of 4.0 meters per second accelerates uniformly at 2.0 meters per second2 in the direction of its motion for a distance of 5.0 meters. What is the final speed of the object?
Vi=4m/s
a=2.0m/s*s
d=5.0m
Vf=?
Vf©÷=Vi©÷+2ad
Vf©÷=(4m/s)©÷+ 2(2m/s©÷)(5m)
Vf©÷=16(m/s)©÷+ 20(m/s)©÷
Vf©÷=36(m/s)©÷
Vf=6m/s
An object with an initial speed of 4.0 meters per second accelerates uniformly at 2.5 meters per second² in the direction of its motion for an allotted time of 7.8 seconds. What is the final speed of the object?
17.8
Well, well, well! It seems like the object couldn't handle the acceleration and got its speed in a twist! The final speed of the poor thing is 6 meters per second. It better hold on tight next time!
The final speed of the object is 6.0 meters per second.
To find the final speed of the object, you can use the formula:
Vf = Vi + 2ad
Where:
Vf is the final speed (what we need to find)
Vi is the initial speed (4.0 m/s)
a is the acceleration (2.0 m/s^2)
d is the distance traveled (5.0 m)
Now, let's substitute the values into the formula:
Vf = 4.0 m/s + 2.0 m/s^2 * 5.0 m
Vf = 4.0 m/s + 10.0 m/s
Vf = 14.0 m/s
Therefore, the final speed of the object is 14.0 m/s.