I have a line equation whose slope is -2 and passes through(-1,6) I have a slope intercept form of y=-2x+4 is this correct or could this be -2x+8

Hey, learn to put your solution back in to check. If y = -2x+4

slope is -2 of course
now check the point
6 = -2(-1) +4 ???
6 = 2+4 yes, so correct

To determine the equation of a line with a given slope and a point on the line, you can use the point-slope form of a linear equation.

The point-slope form is given by: y - y₁ = m(x - x₁), where (x₁, y₁) is the given point, and m is the slope.

In this case, the slope is -2, and the point on the line is (-1, 6). Plugging these values into the point-slope form, we get:

y - 6 = -2(x - (-1))

Simplifying this equation, we have:

y - 6 = -2(x + 1)
y - 6 = -2x - 2

Finally, if we rearrange the equation to the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we get:

y = -2x + 4

So, in this case, the correct equation of the line is y = -2x + 4, and not y = -2x + 8.