C7H6O3+CH3OH→C8H8O3+H2O
In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?
From my understanding the equation is already balanced, correct?
My answer: 26.7%, is this correct?
Work: (11.20gCH3OH)(1 mol CH3OH)/32.05gCH3OH=0.3495gCH3OH
0.3495g/1.31g= 26.68%
I am still getting the same answer
76.9
Well, you've certainly done the calculations correctly, but let me give you a humorously different perspective on this.
Percent yield can be a bit like a pizza delivery guy trying to find the correct address. You ordered a pizza with all the right ingredients (salicyclic acid and methanol) and expected it to transform into a deliciously cheesy methyl salicylate.
Now, sometimes things don't go exactly as planned. Maybe the pizza delivery guy got lost, maybe the oven wasn't hot enough, who knows? In this case, you ended up with only 1.31 grams of your desired product out of the 1.50 grams of salicyclic acid you started with.
So, to calculate the percent yield, you divide the actual amount of product obtained (1.31g) by the theoretical amount of product you should have obtained (1.50g), and multiply it by 100 to get a percentage. In this scenario, you ended up with a 26.68% yield, which means you didn't quite get the full pizza you ordered.
But hey, don't be too disappointed! It's always a learning experience, and sometimes pizza deliveries (or chemical reactions) can be a little unpredictable. Just remember to tip your pizza delivery guy better next time, maybe it'll boost your percent yield!
Your equation is correct, and your calculation to determine the amount of CH3OH used in the reaction is also correct. However, there seems to be a mistake in your calculation for the percent yield.
To calculate the percent yield, you need to divide the actual yield (1.31g) by the theoretical yield (the maximum amount of product that can be obtained based on stoichiometry) and multiply by 100.
To calculate the theoretical yield of methyl salicylate (C8H8O3), you need to determine the number of moles of salicylic acid (C7H6O3) reacted and then use stoichiometry to find the number of moles of methyl salicylate produced.
Here's how you can calculate it:
1. Determine the number of moles of salicylic acid:
- Mass of salicylic acid = 1.50g
- Molar mass of salicylic acid (C7H6O3) = 138.12 g/mol
- Moles of salicylic acid = Mass / Molar mass = 1.50g / 138.12 g/mol = 0.01086 mol
2. Use the stoichiometry of the balanced equation to find the number of moles of methyl salicylate produced:
- From the balanced equation, the ratio of moles of salicylic acid to moles of methyl salicylate is 1:1.
- Therefore, the number of moles of methyl salicylate produced is also 0.01086 mol.
3. Calculate the theoretical yield of methyl salicylate:
- Molar mass of methyl salicylate (C8H8O3) = 152.15 g/mol
- Theoretical yield = Moles of methyl salicylate * Molar mass = 0.01086 mol * 152.15 g/mol = 1.654 g
4. Calculate the percent yield:
- Percent yield = (Actual yield / Theoretical yield) * 100
- Percent yield = (1.31 g / 1.654 g) * 100 = 79.28%
So, the correct percent yield is approximately 79.28%, not 26.68%.
You know it is a limiting reagent problem when BOTH reactants are given.
1. Write the equation and balance it. I think everything is 1:1:1:1
2a. Convert 11.2 grams methanol to moles. moles = grams/molar mass.
2b. Convert 1.5 g salicylic acid to moles the same way.
3a. Using the coefficients in the balanced equation, convert moles methanol to moles of methyl salicylate.
3b. Using same procedure, convert moles salicylic acid to moles methyl salicylate.
3c. It is more than likely that the answers to 3a and 3b will be different which means one of them is wrong. The correct answer in limiting reagent problems is ALWAYS the smaller value and the reactant providing that smaller value is the limiting reagent.
4. Convert the value from 3c to grams. g = moles x molar mass. This is the theoretical yield.
5. Percent yield = (actual yield/theoretical yield)*100 = ??