Ask questions and get helpful answers.

A light string has its ends tied to two walls separated by a distance equal to five-eighths the length of the string. A 53 kg mass is suspended from the center of the string, applying a tension in the string.

What is the tension in the two strings of length L/2 tied to the wall? The acceleration of gravity is 9.8 m/s^2.
Answer in units of N.

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
2 answers
  1. Draw the triangles.

    half the weight is supported by each side.

    Let theta be the angle from the wall horizontal to the string. Then on each side, SinTheta=Weight/(2*tension)

    But tan cosTheta= half wall distance/halfstring distance
    costheta= 5/8

    But sin^2theta+cos^2theta=1
    or weight^2/4Tension^2+25/64=1
    solve for tension.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    👤
    bobpursley
  2. on a calculator it should look like:
    nSolve((53*9.8/2*x)^2+(5/8)^2=1,x)

    *=multiply

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.