Co(s) as electrodes along with their appropriate solutions.
Co2+(aq) + 2e- --> Co(s) -0.28 V
Pb2+(aq) + 2e- --> Pb(s) -0.13 V
The oxidation reaction is
Co(s) --> Co2+(aq) + 2e- +0.28V
E0 net(cell) = E0 ox + E0 red
= (0.28 V) + (-0.13 V)
= +0.15 V
Does this look right? I am not sure if I answered what the question is asking.
Yes, that look fine to me. And your calculations are above reproach.
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