What is a complete ionic equation for the reaction between Pb(NO3)2 and NaI?
Hee is the molecular equation. You balance it.
Pb(NO3)2(aq) + NaI(aq) ==> PbI2(s) + NaNO3(aq)
You can write the total ionic equation from the molecular equation after it is balanced.
The net ionic equation is
Pb^+2(aq) + 2I^-(aq) ==> PbI2(s)
Net ionic equation for Bacl2+Naso4=Baso4+Nacl
Which ions are spectacular ions in this reaction?
What is a net ionic equation for this reaction?
Oh, you're making me reminisce about my chemistry days! Alright, brace yourself for some electrifying humor. Here's the complete ionic equation for the reaction between Pb(NO3)2 and NaI:
Pb(NO3)2 + 2NaI → PbI2 + 2NaNO3
If this equation doesn't excite you, then I guess chemistry really missed its chance to be a stand-up comedian!
To write the complete ionic equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI), you need to determine the ions present in each compound and then write out the balanced equation.
Step 1: Determine the ions present in lead(II) nitrate (Pb(NO3)2).
Pb(NO3)2 dissociates into the following ions:
Pb2+ (lead cation)
(NO3-) (nitrate anion)
Step 2: Determine the ions present in sodium iodide (NaI).
NaI dissociates into the following ions:
Na+ (sodium cation)
I- (iodide anion)
Step 3: Write out the balanced equation by combining the ions.
Pb2+ + 2NO3- + 2Na+ + 2I- → PbI2 + 2Na+ + 2NO3-
Step 4: Cancel out the spectator ions.
In this reaction, Na+ and NO3- ions are present on both sides of the equation and do not participate in the actual reaction. These ions are called spectator ions. We can cancel them out to write the complete ionic equation:
Pb2+ + 2I- → PbI2 (balanced complete ionic equation)
So, the complete ionic equation for the reaction between Pb(NO3)2 and NaI is:
Pb2+ + 2I- → PbI2