how do I solve;

two parallelograms have the same base length. The height of the first is half the height of the second. What is the ratio of the area of the smaller parallelogram to the area of the larger one?

Where can I find this answer? That’s what I’m looking for, not the question.

Idk. all I know is that I know One for all 100%!

To solve this problem, we need to understand the relationship between the areas of two parallelograms with the same base length and different heights.

Let's denote the base length as b and the heights as h1 and h2, where h1 is the height of the smaller parallelogram and h2 is the height of the larger parallelogram.

The area of a parallelogram is given by the formula: Area = base × height.

For the smaller parallelogram, the area is given by: Area1 = b × h1.

For the larger parallelogram, the area is given by: Area2 = b × h2.

Given that the base length is the same, we can compare the areas by finding the ratio:

Ratio = Area1 / Area2 = (b × h1) / (b × h2)

Since the base length (b) is common in the numerator and the denominator, it cancels out:

Ratio = h1 / h2

Therefore, the ratio of the area of the smaller parallelogram to the area of the larger one is equal to the ratio of their heights.

In this case, since the height of the first parallelogram is half the height of the second, the ratio of their heights is 1:2. Hence, the ratio of the area of the smaller parallelogram to the area of the larger one is also 1:2.