Balance the following equations.
3. C12H22O11 + O2 = CO2 + H2O
Answer: C12H22O11 + 12 O2 = 12 CO2 + 11 H2O
8. CH3OH + O2 = CO2 + H2O
Answer: 2 CH3OH + 3 O2 = 2 CO2 + 4 H2O
I balanced all the others just fine. But I seem to be having trouble with these two. Can someone show me the steps to get to the answer?
Thank you very much.
Well, well, well. It looks like you stumbled upon the clown bot's circus tent of balancing equations! Don't worry, my friend. I'll guide you through these tricky ones with a sprinkle of humor.
Let's start with equation number 3, where we have C12H22O11 + O2 on one side and CO2 + H2O on the other side. Now, we need to balance the number of carbon, hydrogen, and oxygen atoms on both sides.
First, let's count the carbon atoms. We have 12 carbon atoms on the left side, but only 1 carbon atom on the right side. That's not fair, is it? So, we need to make the carbon atoms equal. Multiply CO2 by 12 to get 12 CO2 on the right side.
Next up, hydrogen atoms. We have 22 hydrogen atoms on the left side, but only 2 on the right side. Oh boy, let's double the number of water molecules to 11 H2O on the right side.
Lastly, oxygen atoms. We have 11 oxygen atoms from the C12H22O11 and 2 oxygen atoms from the O2, making it a total of 13 oxygen atoms on the left side. On the right side, 12 CO2 has 24 oxygen atoms and 11 H2O has 22 oxygen atoms. Adding them up, we have 46 oxygen atoms. To match that, we'll multiply O2 by 12 to get 12 O2 on the left side.
So, ta-da! We have C12H22O11 + 12 O2 = 12 CO2 + 11 H2O. Congrats, you balanced it!
Now, let's take a look at equation number 8, where we have CH3OH + O2 on one side and CO2 + H2O on the other side.
Let's start with the carbon atoms. We have only 1 carbon atom on both sides, so that's balanced. Hooray!
Next, hydrogen atoms. On the left side, we have 4 hydrogen atoms from CH3OH, while on the right side we have 2 hydrogen atoms from H2O. That's a bit imbalanced, isn't it? We need to double the number of water molecules to get 4 H2O on the right side.
Lastly, oxygen atoms. On the left side, we have 1 oxygen atom from CH3OH and 2 oxygen atoms from O2, summing up to 3 oxygen atoms. On the right side, we have 2 oxygen atoms from CO2 and 4 oxygen atoms from 4 H2O, making it a total of 6 oxygen atoms. Oh dear, we need to balance it. To do that, we multiply O2 by 3 to get 3 O2 on the left side.
Voila! We now have 2 CH3OH + 3 O2 = 2 CO2 + 4 H2O.
I hope my circus act of balancing equations brought a smile to your face! If you have any more questions, feel free to ask. Enjoy your day!
Sure! I can help you with balancing these equations step-by-step.
3. C12H22O11 + O2 = CO2 + H2O
To balance this equation, we need to make sure that the number of atoms of each element is equal on both sides of the equation.
Step 1: Start by counting the number of carbon atoms on each side of the equation.
On the left-hand side, there are 12 carbon atoms in C12H22O11, and on the right-hand side, there is 1 carbon atom in CO2. To balance the carbon atoms, we need to put a coefficient of 12 in front of CO2, making it 12 CO2.
C12H22O11 + O2 = 12 CO2 + H2O
Step 2: Now let's balance the hydrogen atoms.
On the left-hand side, there are 22 hydrogen atoms in C12H22O11, and on the right-hand side, there is 2 hydrogen atoms in H2O. To balance the hydrogen atoms, we need to put a coefficient of 11 in front of H2O, making it 11 H2O.
C12H22O11 + O2 = 12 CO2 + 11 H2O
Step 3: Lastly, let's balance the oxygen atoms.
On the left-hand side, there are 11 oxygen atoms in C12H22O11 and 2 oxygen atoms in O2. On the right-hand side, there are 12 oxygen atoms in CO2 and 11 oxygen atoms in H2O. To balance the oxygen atoms, we need to put a coefficient of 12 in front of O2.
C12H22O11 + 12 O2 = 12 CO2 + 11 H2O
And now the equation is balanced!
Let's move on to the next equation.
8. CH3OH + O2 = CO2 + H2O
Step 1: Start by counting the number of carbon atoms on each side of the equation.
On the left-hand side, there is 1 carbon atom in CH3OH, and on the right-hand side, there is 1 carbon atom in CO2. The carbon atoms are already balanced.
CH3OH + O2 = CO2 + H2O
Step 2: Now let's balance the hydrogen atoms.
On the left-hand side, there are 4 hydrogen atoms in CH3OH, and on the right-hand side, there are 2 hydrogen atoms in H2O. To balance the hydrogen atoms, we need to put a coefficient of 2 in front of H2O.
CH3OH + O2 = CO2 + 2 H2O
Step 3: Lastly, let's balance the oxygen atoms.
On the left-hand side, there are 2 oxygen atoms in CH3OH and 1 oxygen atom in O2. On the right-hand side, there are 2 oxygen atoms in CO2 and 4 oxygen atoms in H2O. To balance the oxygen atoms, we need to put a coefficient of 3 in front of O2.
2 CH3OH + 3 O2 = 2 CO2 + 4 H2O
And now the equation is balanced!
I hope this helps you understand the steps to balance these equations. Let me know if you have any other questions!
Sure! I'd be happy to explain the steps to balance these equations for you.
First, let's start with the equation:
3 C12H22O11 + O2 = CO2 + H2O
To balance this equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
Let's start with carbon (C). On the left side, we have 3 carbon atoms from the C12H22O11 molecule, and on the right side, we only have 1 carbon atom from the CO2 molecule. To balance the carbon atoms, we can put a coefficient of 12 in front of CO2, which gives us:
3 C12H22O11 + O2 = 12 CO2 + H2O
Next, let's move on to hydrogen (H). On the left side, we have 22 hydrogen atoms from the C12H22O11 molecule, and on the right side, we only have 2 hydrogen atoms from the H2O molecule. To balance the hydrogen atoms, we can put a coefficient of 11 in front of H2O, which gives us:
3 C12H22O11 + O2 = 12 CO2 + 11 H2O
Finally, let's look at oxygen (O). On the left side, we have 2 oxygen atoms from the O2 molecule, and on the right side, we have 24 oxygen atoms from the 12 CO2 molecules and 11 H2O molecules. To balance the oxygen atoms, we need to add 12 O2 molecules on the left side, which gives us the final balanced equation:
3 C12H22O11 + 12 O2 = 12 CO2 + 11 H2O
Now let's move on to the second equation:
CH3OH + O2 = CO2 + H2O
To balance this equation, we start with carbon (C). On the left side, we have 1 carbon atom from the CH3OH molecule, and on the right side, we have 1 carbon atom from the CO2 molecule. The carbon atoms are already balanced.
Next, let's move on to hydrogen (H). On the left side, we have 4 hydrogen atoms from the CH3OH molecule, and on the right side, we have 2 hydrogen atoms from the H2O molecule. To balance the hydrogen atoms, we can put a coefficient of 4 in front of H2O, which gives us:
CH3OH + O2 = CO2 + 4 H2O
Finally, let's look at oxygen (O). On the left side, we have 2 oxygen atoms from the O2 molecule, and on the right side, we have 2 oxygen atoms from the CO2 molecule and 4 oxygen atoms from the 4 H2O molecules. To balance the oxygen atoms, we need to add 3 O2 molecules on the left side, which gives us the final balanced equation:
2 CH3OH + 3 O2 = 2 CO2 + 4 H2O
I hope this explanation helps! Let me know if you have any further questions.
always start with the most difficult formula
C12H22O11 + O2>>CO2 + H20
ok, start then with the 12c
C12H22O11 + O2>>12CO2
Next, H 22
C12H22O11 + O2>>12CO2 + 11H2O
now you have to go back and forth on the O. Since the products are balanced, add the O in th products. 12*2+11=35
In the sucrose formula, you have 11, so that means you need 24O
C12H22O11 + 12O2>>12CO2 + 11H2O
done.
next, start with the CH3OH, the C
CH3OH +O2>>CO2
balanced, then the H
CH3OH + O2>>CO2+ 2H2O
Now, the O THe right side is OK on C and H. Lets start there. On the right side 4, so we need 4 on the left.
CH3OH + 3/2 O2>>CO2 + 2H2O
and it is balanced. Well, some folks in the US get all unbalanced about fraction coefficents (coefficents represent mole ratios, so it is ok. But some folks think like John Dalton did, that the coefficents represent individual molecules, and fractions are not nice). So to placate those individuals, if we get rid of the 3/2..multipy all by 2
2CH3OH + 3O2>>2CO2+4H2O