A student placed 14.0g of glucose (C6H1206) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 35.0-mL sample of this glucose solution was diluted to 0.500mL . How many grams of glucose are in 100mL. of the final solution?
To determine the number of grams of glucose in the final solution, we need to use the concept of dilution.
First, let's calculate the concentration of the glucose solution before dilution:
- The student used 14.0g of glucose to prepare a solution with a volume of 100 mL.
- Therefore, the concentration of the solution before dilution can be calculated as follows:
concentration = mass of solute / volume of solution
concentration = 14.0g / 100 mL
Next, let's calculate the concentration of the final solution after dilution:
- A 35.0 mL sample is taken from the original solution and diluted to 500 mL.
- The dilution factor can be calculated as:
dilution factor = volume final solution / volume initial solution
dilution factor = 500 mL / 35.0 mL
- Now, let's find the concentration of the final solution after dilution using the dilution factor:
concentration final solution = concentration initial solution / dilution factor
concentration final solution = (14.0g / 100 mL) / (500 mL / 35.0 mL)
Finally, let's calculate the number of grams of glucose in the final solution:
- We have the concentration of the final solution, and we know that the volume is 100 mL.
- Therefore, we can calculate the mass as follows:
mass = concentration * volume
mass = (concentration final solution) * 100 mL
Please note that for accurate calculations, the density of the final solution would need to be known.
To find the number of grams of glucose in 100 mL of the final solution, we need to use the information given from the given data.
First, let's find the concentration of the original glucose solution:
Concentration (Molarity) = moles of solute / volume of solution (in liters)
We have 14.0 grams of glucose, and the molar mass of glucose is 180.16 g/mol. So, the number of moles of glucose is:
Moles of glucose = 14.0 g / 180.16 g/mol
Next, we need to calculate the volume of the final 35.0 mL diluted solution:
Volume (in liters) = 35.0 mL / 1000 mL/L
Now, we can use the diluted solution volume and moles of glucose to find the concentration of the diluted solution:
Concentration (Molarity) = Moles of glucose / Volume of diluted solution
Next, let's find the moles of glucose in the diluted solution:
Moles of glucose in the diluted solution = Concentration (Molarity) * Volume of diluted solution
Now, we know the moles of glucose in the diluted solution. To find the grams of glucose in 100 mL of the final solution, we need to use the given dilution factor:
Dilution factor = Volume of final solution (100 mL) / Volume of diluted solution (35.0 mL)
Finally, we can calculate the grams of glucose in 100 mL of the final solution using the following formula:
Grams of glucose in 100 mL = Moles of glucose in the diluted solution * Dilution factor * Molar mass of glucose
By plugging in the values into the above formula, you will be able to find the grams of glucose in 100 mL of the final solution.